Steply

Shirts cost $10 and hats cost $6. Max can spend at most $60. Can he…

Step by step, with the reason for every step · Two things, one total · Algebra 1

Step by step

The question

Question: Shirts cost $10 and hats cost $6.

Max can spend at most $60.

Can he buy 3 hats and 4 shirts?

1 Find what we know

What do we know?

Shirts cost $10 each.

Hats cost $6 each.

Max can spend $60 or less.

What do we want?

To know if 3 hats and 4 shirts fit.

2 Name the unknowns

We don't know how many shirts.

We call that number x.

x = number of shirts

We don't know how many hats either.

It is a different number, so it gets its own letter: y.

y = number of hats

3 Write the inequality

One shirt costs $10.

So x shirts cost 10 times x: 10x.

x shirts: 10 × x = 10x

One hat costs $6.

So y hats cost 6 times y: 6y.

y hats: 6 × y = 6y

At most $60 means $60 or less.

That is the sign less than or equal to.

at most $60 = $60 or less: ≤

In words: the shirt money plus the hat money is at most $60.

10x + 6y = 60

So the inequality is 10x + 6y ≤ 60.

10x + 6y ≤ 60

Careful!

At most means 60 or less.

So the sign is less than or equal to, not more than.

Careful: not 10x + 6y ≥ 60 ✗

4 Put the point in

4 shirts: x = 4.

3 hats: y = 3.

As a point, that is (4, 3).

x = 4 , y = 3 (4, 3)

We put them in.

Is it less than or equal to 60?

We don't know yet.

10 × 4 + 6 × 3 ≤? 60

10 times 4 is 40.

6 times 3 is 18.

10 × 4 = 40
6 × 3 = 18

40 plus 18 is 58.

40 + 18 ≤? 60

Is 58 less than or equal to 60?

Yes.

True!

58 ≤ 60 true

5 Answer the question

Yes: 4 shirts and 3 hats cost $58.

6 Check

Let's check with the money.

$2 is left, not below 0.

So Max can pay.

It works!

$60 − $58 = $2 left

Let's look back.

First: find what we know.

Then: name the unknowns.

Then: write the inequality.

Then: put the point in.

Then: answer the question.

Last: check.

Answer
58 ≤ 60 true

Your turn

Try this one yourself, then check:

Show the answer
Yes, $64

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