Steply

Solve 2|x - 1| + 3 < 11

Step by step, with the reason for every step · Absolute value inequalities · Algebra 1

Step by step

The question

Question: solve 2|x − 1| + 3 < 11.

2|x − 1| + 3 < 11

1 Get the bars alone

We want the bars by themselves.

The + 3 is in the way, so we take away 3 on both sides.

2|x − 1| + 3 − 3 < 11 − 3

+ 3 and − 3 make zero.

Cross them out.

11 minus 3 is 8.

2|x − 1| < 8

To remove times 2, we divide both sides by 2.

2 is a positive number, so the sign stays the same.

2|x − 1|2 < 82

2 divided by 2 is 1.

So just the bars is left.

8 divided by 2 is 4.

|x − 1| < 4

2 Draw the distance

3 Write it without bars

So x − 1 is between −4 and 4: −4 < x − 1 < 4.

Now x is in the middle.

−4 < x − 1 < 4

4 Remove the − 1

We want x by itself.

The − 1 is in the way.

To remove − 1, we add 1.

We do it to all three parts.

Why all three?

The signs compare the three parts.

If we change only one part, the answer can change.

−4 + 1 < x − 1 + 1 < 4 + 1

− 1 and + 1 make zero.

Cross them out.

−4 plus 1 is −3.

4 plus 1 is 5.

−4 + 1 = −3
4 + 1 = 5

Now we have −3 < x < 5.

So x is between −3 and 5: −3 < x < 5.

−3 < x < 5

5 Show it on a number line

Books also write the answer like this.

It is called interval notation.

A round bracket means the end is not in, like the open circle.

interval: (−3, 5)

6 Check

Let's test one number from the answer: 2.

We put it in the question.

The inside is 1, and the bars make it 1.

x = 2: 2|2 − 1| + 3 = 2|1| + 3 = 2(1) + 3
= 5

5 is less than 11.

True!

So the answer works.

5 < 11

Let's look back.

First: get the bars alone.

Then: draw the distance.

Then: write it without bars.

Then: remove the − 1.

Then: show it on a number line.

Last: check.

Answer
−3 < x < 5

Your turn

Try this one yourself, then check:

Solve 2|x − 1| + 6 < 16
Show the answer
−4 < x < 6

More from Absolute value inequalities

The whole lesson: Absolute value inequalities →