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Solve 2x + 3y = 8, 3x - 2y = -1

Step by step, with the reason for every step · Systems of equations · Algebra 1

Step by step

The question

Question: solve 2x + 3y = 8 and 3x − 2y = −1.

2x + 3y = 8①

We call them ① and ②.

We want the x and y that make both true.

We will add the equations to remove one letter.

This way is called elimination.

3x − 2y = −1②

1 Make the y numbers opposite

We want to remove y.

In ① it is 3y, in ② it is −2y.

We make them opposite: 6y and −6y.

Then adding removes y.

We multiply every part of ① by 2.

We do it on both sides, so they stay equal.

2 × (2x + 3y) = 2 × 8① × 2

2 times 2x is 4x.

2 times 3y is 6y.

2 times 8 is 16.

2 × 2x = 4x, 2 × 3y = 6y, 2 × 8 = 16

We call it ③.

4x + 6y = 16③

We multiply every part of ② by 3.

We do it on both sides, so they stay equal.

3 × (3x − 2y) = 3 × (−1)② × 3

3 times 3x is 9x.

3 times −2y is −6y.

3 times −1 is −3.

3 × 3x = 9x, 3 × (−2y) = −6y, 3 × (−1) = −3

We call it ④.

9x − 6y = −3④

2 Add the equations

We write ③ and ④ under each other: x under x, y under y.

4x + 6y = 16③
9x − 6y = −3④

Look at y: 6y and −6y.

They are opposites.

Added, they make zero.

Why can we add equations?

Both sides of ④ are the same amount.

So we add the same amount to both sides of ③.

6y and −6y make zero.

Cross them out.

We add ③ and ④: the x parts together, and the numbers together.

4x + 9x = 13x.

16 + (−3) = 13.

4x + 9x = 13x
16 + (−3) = 13

Now we have 13x = 13.

13x = 13

3 Find x

13x means 13 times x.

We want just x.

To remove times 13, we divide by 13.

We do it on both sides, so they stay equal.

13x13 = 1313

13 divided by 13 is 1.

So just x is left.

On the right too: 13 divided by 13 is 1.

1313 = 1

So x = 1.

x = 1

4 Find y

We put x = 1 into ①.

2 times 1 is 2.

2(1) + 3y = 8

Now we have 2 + 3y = 8.

2 + 3y = 8

We want y by itself.

The 2 is in the way.

To remove 2, we take away 2.

We do it on both sides, so they stay equal.

2 + 3y − 2 = 8 − 2

2 and − 2 make zero.

Cross them out.

8 minus 2 is 6.

8 − 2 = 6

Now we have 3y = 6.

3y = 6

3y means 3 times y.

We want just y.

To remove times 3, we divide by 3.

We do it on both sides, so they stay equal.

3y3 = 63

3 divided by 3 is 1.

So just y is left.

6 divided by 3 is 2.

63 = 2

So y = 2.

y = 2

So x = 1 and y = 2, both at the same time.

We write it as (1, 2).

On a graph, it is the point where the two lines meet.

(x, y) = (1, 2)

5 Check

Let's check in both equations.

We put x = 1 and y = 2 into ①.

① 2(1) + 3(2) = 2 + 6 = 8

We get 8, the same as the right side.

Now ②.

② 3(1) − 2(2) = 3 − 4 = −1

We get −1, the same as the right side.

Both work.

So the answer is right!

Let's look back.

First: make the y numbers opposite.

Then: add the equations.

Then: find x.

Then: find y.

Last: check.

Answer
(x, y) = (1, 2)

Your turn

Try this one yourself, then check:

Solve 2x + 4y = 10, 3x − 3y = 6
Show the answer
(x, y) = (3, 1)

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