Worked examples
The question
Question: solve y = 2x + 1 and 3x + y = 11.
y = 2x + 1①
We call them ① and ②.
We want the x and y that make both true.
3x + y = 11②
1 Put ① into ②
In ①, y is already alone.
y is the same as 2x + 1.
So in ②, we write (2x + 1) in place of y.
The brackets keep it together.
Putting one thing in place of another is called substitution.
3x + (2x + 1) = 11
2 Find x
A bracket with a plus or nothing in front can just be removed.
3x + 2x + 1 = 11
Terms are the parts between the + and − signs.
Like terms are the same kind: same letters, same powers.
All the x terms go together.
3x + 2x = 5x.
3x + 2x = 5x
Now we have 5x + 1 = 11.
5x + 1 = 11
We want x by itself.
The + 1 is in the way.
To remove + 1, we take away 1.
We do it on both sides, so they stay equal.
5x + 1 − 1 = 11 − 1
+ 1 and − 1 make zero.
Cross them out.
11 minus 1 is 10.
11 − 1 = 10
Now we have 5x = 10.
5x = 10
5x means 5 times x.
We want just x.
To remove times 5, we divide by 5.
We do it on both sides, so they stay equal.
5x5 = 105
5 divided by 5 is 1.
So just x is left.
10 divided by 5 is 2.
105 = 2
So x = 2.
x = 2
3 Find y
Now we put x = 2 into ①.
y = 2(2) + 1
That is 4 + 1.
y = 4 + 1
So y = 5.
y = 5
So x = 2 and y = 5, both at the same time.
We write it as (2, 5).
On a graph, it is the point where the two lines meet.
(x, y) = (2, 5)
4 Check
Let's check in both equations.
We put x = 2 and y = 5 into ①.
① left: 5
And the right side.
right: 2(2) + 1 = 4 + 1 = 5
Both sides are 5.
Now ②.
② 3(2) + 5 = 6 + 5 = 11
We get 11, the same as the right side.
Both work.
So the answer is right!
Let's look back.
First: put ① into ②.
Then: find x.
Then: find y.
Last: check.
▶ Watch it solved
The question
Question: solve x + 3y = 14 and x + y = 6.
x + 3y = 14①
We call them ① and ②.
We want the x and y that make both true.
We will add the equations to remove one letter.
This way is called elimination.
x + y = 6②
1 Make the x numbers opposite
We want to remove x.
In ① it is x, in ② it is x.
We make them opposite: x and −x.
Then adding removes x.
We multiply every part of ② by −1.
We do it on both sides, so they stay equal.
−1 × (x + y) = −1 × 6② × −1
−1 times x is −x.
−1 times y is −y.
−1 times 6 is −6.
−1 × x = −x, −1 × y = −y, −1 × 6 = −6
We call it ③.
−x − y = −6③
2 Add the equations
We write ① and ③ under each other: x under x, y under y.
x + 3y = 14①
−x − y = −6③
Look at x: x and −x.
They are opposites.
Added, they make zero.
Why can we add equations?
Both sides of ③ are the same amount.
So we add the same amount to both sides of ①.
x and −x make zero.
Cross them out.
We add ① and ③: the y parts together, and the numbers together.
3y − y = 2y.
14 + (−6) = 8.
3y − y = 2y
14 + (−6) = 8
Now we have 2y = 8.
2y = 8
3 Find y
2y means 2 times y.
We want just y.
To remove times 2, we divide by 2.
We do it on both sides, so they stay equal.
2y2 = 82
2 divided by 2 is 1.
So just y is left.
8 divided by 2 is 4.
82 = 4
So y = 4.
y = 4
4 Find x
We put y = 4 into ①.
3 times 4 is 12.
x + 3(4) = 14
Now we have x + 12 = 14.
x + 12 = 14
We want x by itself.
The + 12 is in the way.
To remove + 12, we take away 12.
We do it on both sides, so they stay equal.
x + 12 − 12 = 14 − 12
+ 12 and − 12 make zero.
Cross them out.
14 minus 12 is 2.
14 − 12 = 2
So x = 2.
x = 2
So x = 2 and y = 4, both at the same time.
We write it as (2, 4).
On a graph, it is the point where the two lines meet.
(x, y) = (2, 4)
5 Check
Let's check in both equations.
We put x = 2 and y = 4 into ①.
① 2 + 3(4) = 2 + 12 = 14
We get 14, the same as the right side.
Now ②.
② 2 + 4 = 6
We get 6, the same as the right side.
Both work.
So the answer is right!
Let's look back.
First: make the x numbers opposite.
Then: add the equations.
Then: find y.
Then: find x.
Last: check.
▶ Watch it solved
The question
Question: solve 3x + 2y = 16 and 2x + 3y = 14.
3x + 2y = 16①
We call them ① and ②.
We want the x and y that make both true.
We will add the equations to remove one letter.
This way is called elimination.
2x + 3y = 14②
1 Make the x numbers opposite
We want to remove x.
In ① it is 3x, in ② it is 2x.
We make them opposite: 6x and −6x.
Then adding removes x.
We multiply every part of ① by 2.
We do it on both sides, so they stay equal.
2 × (3x + 2y) = 2 × 16① × 2
2 times 3x is 6x.
2 times 2y is 4y.
2 times 16 is 32.
2 × 3x = 6x, 2 × 2y = 4y, 2 × 16 = 32
We call it ③.
6x + 4y = 32③
We multiply every part of ② by −3.
We do it on both sides, so they stay equal.
−3 × (2x + 3y) = −3 × 14② × −3
−3 times 2x is −6x.
−3 times 3y is −9y.
−3 times 14 is −42.
−3 × 2x = −6x, −3 × 3y = −9y, −3 × 14 = −42
We call it ④.
−6x − 9y = −42④
2 Add the equations
We write ③ and ④ under each other: x under x, y under y.
6x + 4y = 32③
−6x − 9y = −42④
Look at x: 6x and −6x.
They are opposites.
Added, they make zero.
Why can we add equations?
Both sides of ④ are the same amount.
So we add the same amount to both sides of ③.
6x and −6x make zero.
Cross them out.
We add ③ and ④: the y parts together, and the numbers together.
4y − 9y = −5y.
32 + (−42) = −10.
4y − 9y = −5y
32 + (−42) = −10
Now we have −5y = −10.
−5y = −10
3 Find y
−5y means −5 times y.
We want just y.
To remove times −5, we divide by −5.
We do it on both sides, so they stay equal.
−5y−5 = −10−5
−5 divided by −5 is 1.
So just y is left.
−10 divided by −5 is 2.
−10−5 = 2
So y = 2.
y = 2
4 Find x
We put y = 2 into ①.
2 times 2 is 4.
3x + 2(2) = 16
Now we have 3x + 4 = 16.
3x + 4 = 16
We want x by itself.
The + 4 is in the way.
To remove + 4, we take away 4.
We do it on both sides, so they stay equal.
3x + 4 − 4 = 16 − 4
+ 4 and − 4 make zero.
Cross them out.
16 minus 4 is 12.
16 − 4 = 12
Now we have 3x = 12.
3x = 12
3x means 3 times x.
We want just x.
To remove times 3, we divide by 3.
We do it on both sides, so they stay equal.
3x3 = 123
3 divided by 3 is 1.
So just x is left.
12 divided by 3 is 4.
123 = 4
So x = 4.
x = 4
So x = 4 and y = 2, both at the same time.
We write it as (4, 2).
On a graph, it is the point where the two lines meet.
(x, y) = (4, 2)
5 Check
Let's check in both equations.
We put x = 4 and y = 2 into ①.
① 3(4) + 2(2) = 12 + 4 = 16
We get 16, the same as the right side.
Now ②.
② 2(4) + 3(2) = 8 + 6 = 14
We get 14, the same as the right side.
Both work.
So the answer is right!
Let's look back.
First: make the x numbers opposite.
Then: add the equations.
Then: find y.
Then: find x.
Last: check.
▶ Watch it solved