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Systems of equations

Substitution, elimination · Algebra 1 · 22 problems, easy to harder

▶ Watch the first one solved

How we do it

  1. Make the x numbers opposite
  2. Add the equations
  3. Find y
  4. Find x
  5. Check

The steps for Solve x + 3y = 14; x + y = 6. Every solution names its steps, so you always know what comes next.

Worked examples

Solve y = 2x + 1, 3x + y = 11 Easy

The question

Question: solve y = 2x + 1 and 3x + y = 11.

y = 2x + 1①

We call them ① and ②.

We want the x and y that make both true.

3x + y = 11②

1 Put ① into ②

In ①, y is already alone.

y is the same as 2x + 1.

So in ②, we write (2x + 1) in place of y.

The brackets keep it together.

Putting one thing in place of another is called substitution.

3x + (2x + 1) = 11

2 Find x

A bracket with a plus or nothing in front can just be removed.

3x + 2x + 1 = 11

Terms are the parts between the + and − signs.

Like terms are the same kind: same letters, same powers.

All the x terms go together.

3x + 2x = 5x.

3x + 2x = 5x

Now we have 5x + 1 = 11.

5x + 1 = 11

We want x by itself.

The + 1 is in the way.

To remove + 1, we take away 1.

We do it on both sides, so they stay equal.

5x + 1 − 1 = 11 − 1

+ 1 and − 1 make zero.

Cross them out.

11 minus 1 is 10.

11 − 1 = 10

Now we have 5x = 10.

5x = 10

5x means 5 times x.

We want just x.

To remove times 5, we divide by 5.

We do it on both sides, so they stay equal.

5x5 = 105

5 divided by 5 is 1.

So just x is left.

10 divided by 5 is 2.

105 = 2

So x = 2.

x = 2

3 Find y

Now we put x = 2 into ①.

y = 2(2) + 1

That is 4 + 1.

y = 4 + 1

So y = 5.

y = 5

So x = 2 and y = 5, both at the same time.

We write it as (2, 5).

On a graph, it is the point where the two lines meet.

(x, y) = (2, 5)

4 Check

Let's check in both equations.

We put x = 2 and y = 5 into ①.

① left: 5

And the right side.

right: 2(2) + 1 = 4 + 1 = 5

Both sides are 5.

Now ②.

② 3(2) + 5 = 6 + 5 = 11

We get 11, the same as the right side.

Both work.

So the answer is right!

Let's look back.

First: put ① into ②.

Then: find x.

Then: find y.

Last: check.

Answer
(x, y) = (2, 5)

▶ Watch it solved

Solve x + 3y = 14; x + y = 6 Medium

The question

Question: solve x + 3y = 14 and x + y = 6.

x + 3y = 14①

We call them ① and ②.

We want the x and y that make both true.

We will add the equations to remove one letter.

This way is called elimination.

x + y = 6②

1 Make the x numbers opposite

We want to remove x.

In ① it is x, in ② it is x.

We make them opposite: x and −x.

Then adding removes x.

We multiply every part of ② by −1.

We do it on both sides, so they stay equal.

−1 × (x + y) = −1 × 6② × −1

−1 times x is −x.

−1 times y is −y.

−1 times 6 is −6.

−1 × x = −x, −1 × y = −y, −1 × 6 = −6

We call it ③.

−x − y = −6③

2 Add the equations

We write ① and ③ under each other: x under x, y under y.

x + 3y = 14①
−x − y = −6③

Look at x: x and −x.

They are opposites.

Added, they make zero.

Why can we add equations?

Both sides of ③ are the same amount.

So we add the same amount to both sides of ①.

x and −x make zero.

Cross them out.

We add ① and ③: the y parts together, and the numbers together.

3y − y = 2y.

14 + (−6) = 8.

3y − y = 2y
14 + (−6) = 8

Now we have 2y = 8.

2y = 8

3 Find y

2y means 2 times y.

We want just y.

To remove times 2, we divide by 2.

We do it on both sides, so they stay equal.

2y2 = 82

2 divided by 2 is 1.

So just y is left.

8 divided by 2 is 4.

82 = 4

So y = 4.

y = 4

4 Find x

We put y = 4 into ①.

3 times 4 is 12.

x + 3(4) = 14

Now we have x + 12 = 14.

x + 12 = 14

We want x by itself.

The + 12 is in the way.

To remove + 12, we take away 12.

We do it on both sides, so they stay equal.

x + 12 − 12 = 14 − 12

+ 12 and − 12 make zero.

Cross them out.

14 minus 12 is 2.

14 − 12 = 2

So x = 2.

x = 2

So x = 2 and y = 4, both at the same time.

We write it as (2, 4).

On a graph, it is the point where the two lines meet.

(x, y) = (2, 4)

5 Check

Let's check in both equations.

We put x = 2 and y = 4 into ①.

① 2 + 3(4) = 2 + 12 = 14

We get 14, the same as the right side.

Now ②.

② 2 + 4 = 6

We get 6, the same as the right side.

Both work.

So the answer is right!

Let's look back.

First: make the x numbers opposite.

Then: add the equations.

Then: find y.

Then: find x.

Last: check.

Answer
(x, y) = (2, 4)

▶ Watch it solved

Solve 3x + 2y = 16, 2x + 3y = 14 Harder

The question

Question: solve 3x + 2y = 16 and 2x + 3y = 14.

3x + 2y = 16①

We call them ① and ②.

We want the x and y that make both true.

We will add the equations to remove one letter.

This way is called elimination.

2x + 3y = 14②

1 Make the x numbers opposite

We want to remove x.

In ① it is 3x, in ② it is 2x.

We make them opposite: 6x and −6x.

Then adding removes x.

We multiply every part of ① by 2.

We do it on both sides, so they stay equal.

2 × (3x + 2y) = 2 × 16① × 2

2 times 3x is 6x.

2 times 2y is 4y.

2 times 16 is 32.

2 × 3x = 6x, 2 × 2y = 4y, 2 × 16 = 32

We call it ③.

6x + 4y = 32③

We multiply every part of ② by −3.

We do it on both sides, so they stay equal.

−3 × (2x + 3y) = −3 × 14② × −3

−3 times 2x is −6x.

−3 times 3y is −9y.

−3 times 14 is −42.

−3 × 2x = −6x, −3 × 3y = −9y, −3 × 14 = −42

We call it ④.

−6x − 9y = −42④

2 Add the equations

We write ③ and ④ under each other: x under x, y under y.

6x + 4y = 32③
−6x − 9y = −42④

Look at x: 6x and −6x.

They are opposites.

Added, they make zero.

Why can we add equations?

Both sides of ④ are the same amount.

So we add the same amount to both sides of ③.

6x and −6x make zero.

Cross them out.

We add ③ and ④: the y parts together, and the numbers together.

4y − 9y = −5y.

32 + (−42) = −10.

4y − 9y = −5y
32 + (−42) = −10

Now we have −5y = −10.

−5y = −10

3 Find y

−5y means −5 times y.

We want just y.

To remove times −5, we divide by −5.

We do it on both sides, so they stay equal.

−5y−5 = −10−5

−5 divided by −5 is 1.

So just y is left.

−10 divided by −5 is 2.

−10−5 = 2

So y = 2.

y = 2

4 Find x

We put y = 2 into ①.

2 times 2 is 4.

3x + 2(2) = 16

Now we have 3x + 4 = 16.

3x + 4 = 16

We want x by itself.

The + 4 is in the way.

To remove + 4, we take away 4.

We do it on both sides, so they stay equal.

3x + 4 − 4 = 16 − 4

+ 4 and − 4 make zero.

Cross them out.

16 minus 4 is 12.

16 − 4 = 12

Now we have 3x = 12.

3x = 12

3x means 3 times x.

We want just x.

To remove times 3, we divide by 3.

We do it on both sides, so they stay equal.

3x3 = 123

3 divided by 3 is 1.

So just x is left.

12 divided by 3 is 4.

123 = 4

So x = 4.

x = 4

So x = 4 and y = 2, both at the same time.

We write it as (4, 2).

On a graph, it is the point where the two lines meet.

(x, y) = (4, 2)

5 Check

Let's check in both equations.

We put x = 4 and y = 2 into ①.

① 3(4) + 2(2) = 12 + 4 = 16

We get 16, the same as the right side.

Now ②.

② 2(4) + 3(2) = 8 + 6 = 14

We get 14, the same as the right side.

Both work.

So the answer is right!

Let's look back.

First: make the x numbers opposite.

Then: add the equations.

Then: find y.

Then: find x.

Last: check.

Answer
(x, y) = (4, 2)

▶ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. y = 2x + 1, 3x + y = 11
    Answer
    (x, y) = (2, 5)
  2. y = x + 3, 2x + y = 9
    Answer
    (x, y) = (2, 5)
  3. x = 3y - 2 and 2x + y = 10
    Answer
    (x, y) = (4, 2)
  4. y = 4x, x + y = 10
    Answer
    (x, y) = (2, 8)
  5. x + y = 10, x - y = 2
    Answer
    (x, y) = (6, 4)
  6. x + y = 7, x - y = 3
    Answer
    (x, y) = (5, 2)
  7. 2x + y = 9, x - y = 3
    Answer
    (x, y) = (4, 1)
  8. x + 2y = 8, -x + y = 1
    Answer
    (x, y) = (2, 3)

Medium

  1. x + 3y = 14; x + y = 6
    Answer
    (x, y) = (2, 4)
  2. 2x + 3y = 12, x - y = 1
    Answer
    (x, y) = (3, 2)
  3. y = 3x - 5, y = x + 1
    Answer
    (x, y) = (3, 4)
  4. 3x + y = 5, 2x + y = 2
    Answer
    (x, y) = (3, −4)
  5. x + 2y = 7, 3x - 2y = 5
    Answer
    (x, y) = (3, 2)
  6. y = -x + 4, 2x - y = 5
    Answer
    (x, y) = (3, 1)
  7. 4x - y = 6, x + y = 4
    Answer
    (x, y) = (2, 2)
  8. 2x + y = 1, x + y = -1
    Answer
    (x, y) = (2, −3)
  9. x + y = 5, x + y = 8
    Answer
    0 = −3
  10. 2x + 2y = 10, x + y = 5
    Answer
    0 = 0

Harder

  1. 3x + 2y = 16, 2x + 3y = 14
    Answer
    (x, y) = (4, 2)
  2. 2x + 3y = 8, 3x - 2y = -1
    Answer
    (x, y) = (1, 2)
  3. 5x - 2y = 4, 3x + 4y = 18
    Answer
    (x, y) = (2, 3)
  4. 4x + 3y = 2, 2x - 5y = 14
    Answer
    (x, y) = (2, −2)