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Solve 3 < 2x + 1 < 9

Step by step, with the reason for every step · Compound inequalities · Algebra 1

Step by step

The question

Question: solve 3 < 2x + 1 < 9.

x is in the middle, between two numbers.

3 < 2x + 1 < 9

1 Remove the + 1

We want x by itself.

The + 1 is in the way.

To remove + 1, we take away 1.

We do it to all three parts.

Why all three?

The signs compare the three parts.

If we change only one part, the answer can change.

3 − 1 < 2x + 1 − 1 < 9 − 1

+ 1 and − 1 make zero.

Cross them out.

3 minus 1 is 2.

9 minus 1 is 8.

3 − 1 = 2
9 − 1 = 8

Now we have 2 < 2x < 8.

2 < 2x < 8

2 Remove the 2

2x means 2 times x.

We want just x.

To remove times 2, we divide by 2.

We do it to all three parts.

2 is a positive number, so the signs stay the same.

22 < 2x2 < 82

2 divided by 2 is 1.

So just x is left.

2 divided by 2 is 1.

8 divided by 2 is 4.

22 = 1, 82 = 4

Now we have 1 < x < 4.

So x is between 1 and 4: 1 < x < 4.

1 < x < 4

3 Show it on a number line

Books also write the answer like this.

It is called interval notation.

A round bracket means the end is not in, like the open circle.

interval: (1, 4)

4 Check

Let's test one number from the answer: 3.

We put it in place of x in the middle part.

Middle: 2(3) + 1 = 6 + 1 = 7

7 is greater than 3, and less than 9.

True!

So the answer works.

3 < 7 < 9

Let's look back.

First: remove the + 1.

Then: remove the 2.

Then: show it on a number line.

Last: check.

Answer
1 < x < 4

Your turn

Try this one yourself, then check:

Solve 5 < 4x + 1 < 13
Show the answer
1 < x < 3

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