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Solve -3 < 2x + 1 <= 7

Step by step, with the reason for every step · Compound inequalities · Algebra 1

Step by step

The question

Question: solve −3 < 2x + 1 ≤ 7.

x is in the middle, between two numbers.

−3 < 2x + 1 ≤ 7

1 Remove the + 1

We want x by itself.

The + 1 is in the way.

To remove + 1, we take away 1.

We do it to all three parts.

Why all three?

The signs compare the three parts.

If we change only one part, the answer can change.

−3 − 1 < 2x + 1 − 1 ≤ 7 − 1

+ 1 and − 1 make zero.

Cross them out.

−3 minus 1 is −4.

7 minus 1 is 6.

−3 − 1 = −4
7 − 1 = 6

Now we have −4 < 2x ≤ 6.

−4 < 2x ≤ 6

2 Remove the 2

2x means 2 times x.

We want just x.

To remove times 2, we divide by 2.

We do it to all three parts.

2 is a positive number, so the signs stay the same.

−42 < 2x2 ≤ 62

2 divided by 2 is 1.

So just x is left.

−4 divided by 2 is −2.

6 divided by 2 is 3.

−42 = −2, 62 = 3

Now we have −2 < x ≤ 3.

So x is between −2 and 3: −2 < x ≤ 3.

−2 < x ≤ 3

3 Show it on a number line

Books also write the answer like this.

It is called interval notation.

A round bracket means the end is not in, like the open circle.

A square bracket means the end is in, like the filled circle.

interval: (−2, 3]

4 Check

Let's test one number from the answer: 1.

We put it in place of x in the middle part.

Middle: 2(1) + 1 = 2 + 1 = 3

3 is greater than −3, and less than or equal to 7.

True!

So the answer works.

−3 < 3 ≤ 7

Let's look back.

First: remove the + 1.

Then: remove the 2.

Then: show it on a number line.

Last: check.

Answer
−2 < x ≤ 3

Your turn

Try this one yourself, then check:

Solve −7 < 2x + 1 ≤ 11
Show the answer
−4 < x ≤ 5

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