Step by step
The question
Question: solve sin 3x = 1/2.
Find every angle from 0° up to 360°.
We want the angles from 0° to 360°: one full turn.
1 Name the angle
The angle here is 3x, not x.
We give it a name: u = 3x.
Then the equation is sin u = 1/2: the kind we can already solve.
2 Find how far u goes
x goes from 0° to 360°.
Times 3 on every part: u = 3x goes 3 times as far, from 0° up to 1080°.
1080° is 3 full turns of the circle.
So u can land on each point 3 times.
3 Find u in the first turn
From the unit circle: sin 30° = 1/2.
So the reference angle is 30°.
Sin is the up value.
The points with that height are on a flat line.
Sin is positive above the x-axis: quadrants I and II.
30° and 180° − 30°: u = 30° or 150°.
On the circle: 2 points.
4 Add full turns
The next turn lands on the same points again: add 360°.
30° + 360° is 390°.
390° + 360° is 750°.
Careful!
Do not stop after one turn!
u goes round 3 times, so every point gives 3 angles.
The same for 150°: 510° and 870°.
5 Divide by 3
u is 3x.
So x is u divided by 3.
30° ÷ 3 is 10°.
150° ÷ 3 is 50°.
And so on.
All are from 0° to 360°.
So x = 10°, 50°, 130°, 170°, 250°, 290°.
6 Check
Let's check every answer.
Put it in, times 3 first, then the unit circle.
Each one must give 1/2.
Every answer works.
So x = 10°, 50°, 130°, 170°, 250°, 290°.
Let's look back.
First: name the angle.
Then: find how far u goes.
Then: find u in the first turn.
Then: add full turns.
Then: divide by 3.
Last: check.