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Solve √(4x + 1) = √(2x + 7)

Step by step, with the reason for every step · Square root equations · Algebra 2

Step by step

The question

Question: solve √(4x + 1) = √(2x + 7).

√4x + 1 = √2x + 7

1 Square both sides

Squaring removes the square root.

The square root of 9 is 3, and 3 squared is 9 again.

(√9)² = 9

We square both sides, so they stay equal.

(√4x + 1)2 = (√2x + 7)2

The squares remove both square roots.

4x + 1 = 2x + 7

2 Get x on one side

There is x on both sides.

We want x on one side only.

So we remove the 2x from the right side.

To remove 2x, we take away 2x.

We do it on both sides, so they stay equal.

4x + 1 − 2x = 2x + 7 − 2x

2x and − 2x make zero.

Cross them out.

4x − 2x = 2x.

4x − 2x = 2x

Now we have 2x + 1 = 7.

2x + 1 = 7

We want x by itself.

Two things are stuck to x: times 2 and + 1.

The + 1 is on the outside, so it comes off first.

Then the times 2.

3 Remove the + 1

To remove + 1, we take away 1.

We do it on both sides, so they stay equal.

2x + 1 − 1 = 7 − 1

+ 1 and − 1 make zero.

Cross them out.

7 − 1 = 6.

7 − 1 = 6

Now we have 2x = 6.

2x = 6

4 Remove the 2

2x means 2 times x.

We want just x.

To remove times 2, we divide by 2.

We do it on both sides, so they stay equal.

2x2 = 62

2 divided by 2 is 1.

So just x is left.

6 divided by 2 is 3.

62 = 3

So x = 3!

x = 3

5 Check

Careful!

Squaring can make an answer that does not work.

Why?

Minus 2 squared is 4, and 2 squared is 4 too.

Squaring hides a minus sign.

So we check every answer in the question.

Careful: squaring can make a false answer
(−2)² = 4 and 2² = 4

Let's check x = 3 in the question.

The left side is √13.

x = 3: √4(3) + 1 = √13

The right side is √13.

The same!

x = 3 works.

right side: √2(3) + 7 = √13 ✓

Let's look back.

First: square both sides.

Then: get x on one side.

Then: remove the + 1.

Then: remove the 2.

Last: check.

Answer
x = 3

Your turn

Try this one yourself, then check:

Solve √8x + 1 = √3x + 11
Show the answer
x = 2

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