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Solve x^2 - 16 >= 0

Step by step, with the reason for every step · Quadratic inequalities · Algebra 2

Step by step

The question

Question: solve x² − 16 ≥ 0.

There is an x², so the answer can be two parts.

x2 − 16 ≥ 0

1 Two squares

This is one square take away another square.

x² is x squared.

16 is 4 squared.

A square minus a square is the plus bracket times the minus bracket.

a² − b² = (a + b)(a − b)
x2 = (x)²
16 = 4²

So we get (x + 4)(x − 4) ≥ 0.

(x + 4)(x − 4) ≥ 0

2 Find the critical points

A critical point is an x where the side with x is 0, or has no value.

Only there can its sign change.

critical point: where it is 0 (or ÷ 0)

We make each bracket 0.

x + 4 = 0 x − 4 = 0

In x + 4 = 0, we take away 4 on both sides.

In x − 4 = 0, we add 4 on both sides.

x + 4 − 4 = 0 − 4 x − 4 + 4 = 0 + 4

The critical points are −4 and 4.

x = −4 x = 4

3 Make a sign table

Between the critical points the sign stays the same.

So one test number tells us the sign of each part.

We draw a table.

The critical points −4 and 4 split the number line into 3 parts.

0

At −4, x + 4 is 0.

So the product is 0 there.

0
0

At 4, x − 4 is 0.

So the product is 0 there.

0

Left of −4, we test x = −5.

−5

x + 4 is −1 and x − 4 is −9.

−1
−9

Minus times minus is plus.

Between −4 and 4, we test x = 0.

0

x + 4 is 4 and x − 4 is −4.

4
−4

Plus times minus is minus.

Right of 4, we test x = 5.

5

x + 4 is 9 and x − 4 is 1.

9
1

Plus times plus is plus.

4 Read the answer

Greater than or equal to 0 means positive or 0.

So we want the plus parts, and the 0s.

So x ≤ −4 or x ≥ 4.

x ≤ −4 or x ≥ 4
≥ 0 → the + parts and the 0s

Careful!

Not the minus part!

Greater than 0 means plus.

Careful: not −4 ≤ x ≤ 4 ✗

5 Show it on a number line

Books also write the answer like this.

It is called interval notation.

A square bracket means the end is in, like the filled circle.

∞ means it goes on for ever.

∪ means or.

interval: (−∞, −4] ∪ [4, ∞)

6 Check

Let's check with a picture: the graph of y = x² − 16.

It is a parabola.

It crosses the x-axis at the critical points, −4 and 4.

Above the x-axis, y is plus.

That is x ≤ −4 or x ≥ 4: our answer.

Let's check: a number from the answer, 6, put into the question.

x = 6: 62 − 16 = 36 − 16 = 20

20 is greater than or equal to 0.

True!

20 ≥ 0 true

Let's look back.

First: two squares.

Then: find the critical points.

Then: make a sign table.

Then: read the answer.

Then: show it on a number line.

Last: check.

Answer
Careful: not −4 ≤ x ≤ 4 ✗

Your turn

Try this one yourself, then check:

Solve x2 − 4 ≥ 0
Show the answer
x ≤ −2 or x ≥ 2

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