Step by step
The question
Question: work out the sum for i = 2 to 6 of (i² − 1).
Σi = 26(i2 − 1)
1 Read the sigma
Σ is the Greek letter sigma.
It means: add up.
Start with i = 2, and stop at i = 6.
That is 6 − 2 + 1: 5 terms.
For each i we work out i² − 1.
Σ = add up
start: i = 2, stop: i = 6
6 − 2 + 1 = 5 terms
Careful!
From 2 to 6 there are 5 terms, not 4: we count both ends.
So 6 − 2 + 1.
Careful: 6 − 2 = 4 is not the number of terms
2 Write the terms
i = 2: we put 2 in place of i.
We get 3.
i = 2: 22 − 1 = 4 − 1 = 3
i = 3 gives 8.
i = 3: 32 − 1 = 9 − 1 = 8
i = 4: 42 − 1 = 16 − 1 = 15
i = 5: 52 − 1 = 25 − 1 = 24
And i = 6 gives 35.
That is the last one.
i = 6: 62 − 1 = 36 − 1 = 35
3 Add them
Now we add the 5 terms.
Σi = 26(i2 − 1) = 3 + 8 + 15 + 24 + 35
So the sum is 85.
= 85
4 Check
Let's check: we add them again, backwards.
Backwards: 35 + 24 + 15 + 8 + 3 = 85
We get 85 again.
It works!
Let's look back.
First: read the sigma.
Then: write the terms.
Then: add them.
Last: check.
Answer
= 85