Steply

Terms of -y^2 - 6y + 11

Step by step, with the reason for every step · Parts of an expression · Algebra 1

Step by step

The question

Question: name the terms, the coefficients and the constant of −y² − 6y + 11.

−y2 − 6y + 11

1 Split into terms

Terms are the parts between the + and − signs.

Each sign stays with the term after it.

So the terms are −y², −6y and 11.

= terms: −y2, −6y, 11

Careful!

The minus sign goes with the term.

It is −y², not y².

Careful: not y² ✗

2 Name each part

No number in front means 1.

−y² is minus 1 times y.

−y² = −1 × y²

A coefficient is the number in front of a letter: −1 for y² and −6 for y.

A constant has no letter: 11.

= coefficients: −1, −6 constant: 11

3 Check

Let's check: put the terms back together.

−y² plus −6y plus 11.

Adding a negative is taking away.

We get −y² − 6y + 11 again.

So the answer is right!

−y² + (−6y) + 11 = −y² − 6y + 11

Let's look back.

First: split into terms.

Then: name each part.

Last: check.

Answer
= coefficients: −1, −6 constant: 11

Your turn

Try this one yourself, then check:

Name the terms, the coefficients and the constant of −a2 − 9a + 10
Show the answer
coefficients −1, −9; constant 10

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