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Test mean1 > mean2: mean 34, sd 4, n 16 and mean 32, sd 3, n 9…

Step by step, with the reason for every step · Comparing two groups · University Statistics

Step by step

The question

Question: group 1 has mean 34, SD 4 and size 16; group 2 has mean 32, SD 3 and size 9: at the 5% level, is the first mean more than the second?

μ1 > μ2? x̄1 = 34, σ1 = 4, n1 = 16; x̄2 = 32, σ2 = 3, n2 = 9

The SDs of all the numbers in each group are known.

σ1, σ2: the SDs of all the numbers, known

1 Write the hypotheses

H₀ is the "nothing new" idea: it has the equal sign.

Here: the two means are the same, so the difference is 0.

H0 : μ1 = μ2

Hₐ is what we want to show.

Here: the first mean is more than the second.

Ha : μ1 > μ2

More than: one tail, the right end.

one tail: the right end

2 Standard error

The standard error of the difference: add the two variances, sigma squared over n, then the square root.

SE = √σ12n1 + σ22n2

4 squared over 16 is 1.

3 squared over 9 is 1.

Together 2, and the square root is about 1.4142.

SE = √4216 + 329 = √1 + 1 = √2 ≈ 1.4142

Careful!

Add the variances, then take the square root.

Do not add the two SDs.

Careful: not SE = 1 + 1 = 2 ✗

3 The test number

z is the difference of the means over the SE.

34 minus 32 is 2.

Divided by 1.4142: about 1.41.

z = x̄1 − x̄2SE = 34 − 321.4142 ≈ 1.41

4 The p-value

The p-value is the chance of getting a sample this far out, if H zero is true.

p-value: the chance of a sample this far out, if H0 is true

On the bell of H zero: 0 in the middle, our sample at z = 1.41.

We shade the right end, from our z up.

The z-table gives the area to the left of z.

Row 1.4, column .01.

For z = 1.41: the row 1.4 and the column .01 meet at 0.9207.

The right end is 1 minus 0.9207: 0.0793.

p-value = 1 − 0.9207 = 0.0793

5 Decide

The p-value, 0.0793, is more than alpha, 0.05.

Our sample is not rare enough.

So we do not reject H zero.

= p-value 0.0793 > α = 0.05 → do not reject H0

6 Say it in words

At the 5% level, there is not enough evidence that

In words: at the 5% level, there is not enough evidence that the first mean is more than the second.

the first mean is more than the second.

This does not prove H zero is true.

We just cannot rule it out.

not rejecting H0 does not prove H0

7 Check

Let's check the other way, with the cut-off.

0.05 in the right end gives the cut-off 1.645.

0.05 in one end: cut-off 1.645

z is 1.41: not past the cut-off.

The same decision.

So it is right!

z = 1.41 < 1.645: not past it, do not reject

Let's look back.

First: write the hypotheses.

Then: standard error.

Then: the test number.

Then: the p-value.

Then: decide.

Then: say it in words.

Last: check.

Answer
= p-value 0.0793 > α = 0.05 → do not reject H0

Your turn

Try this one yourself, then check:

Test μ1 > μ2? x̄1 = 33, σ1 = 14, n1 = 49; x̄2 = 30, σ2 = 5, n2 = 25
Show the answer
do not reject H0

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