Step by step
The question
Question: group 1 has mean 52, SD 6 and size 36; group 2 has mean 49, SD 8 and size 64: at the 5% level, is the first mean more than the second?
The SDs of all the numbers in each group are known.
1 Write the hypotheses
H₀ is the "nothing new" idea: it has the equal sign.
Here: the two means are the same, so the difference is 0.
Hₐ is what we want to show.
Here: the first mean is more than the second.
More than: one tail, the right end.
2 Standard error
The standard error of the difference: add the two variances, sigma squared over n, then the square root.
6 squared over 36 is 1.
8 squared over 64 is 1.
Together 2, and the square root is about 1.4142.
Careful!
Add the variances, then take the square root.
Do not add the two SDs.
3 The test number
z is the difference of the means over the SE.
52 minus 49 is 3.
Divided by 1.4142: about 2.12.
4 The p-value
The p-value is the chance of getting a sample this far out, if H zero is true.
On the bell of H zero: 0 in the middle, our sample at z = 2.12.
We shade the right end, from our z up.
The z-table gives the area to the left of z.
Row 2.1, column .02.
For z = 2.12: the row 2.1 and the column .02 meet at 0.9830.
The right end is 1 minus 0.9830: 0.0170.
5 Decide
The p-value, 0.0170, is less than alpha, 0.05.
Our sample would be rare if H zero were true.
So we reject H zero.
6 Say it in words
In words: at the 5% level, there is enough evidence that the first mean is more than the second.
7 Check
Let's check the other way, with the cut-off.
0.05 in the right end gives the cut-off 1.645.
z is 2.12: past the cut-off.
The same decision.
So it is right!
Let's look back.
First: write the hypotheses.
Then: standard error.
Then: the test number.
Then: the p-value.
Then: decide.
Then: say it in words.
Last: check.