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The radius of a circle grows at 2 cm/s. How fast is the area growing…

Step by step, with the reason for every step · Related rates · Calculus

Step by step

The question

Question: The radius of a circle grows at 2 cm/s.

How fast is the area growing when the radius is 5 cm?

1 Draw and name

Draw it.

The radius r grows, so the area A grows too.

The radius grows by 2 cm per second: dr/dt = 2.

drdt = 2 cm/s

dr/dt means how fast r changes: the change each second.

drdt: how fast r changes, per second

We want dA/dt at the moment when r = 5.

dAdt = ?

2 Write the equation

The area of a circle: A = π r squared.

A = πr2

Careful!

Do not put r = 5 in yet!

r changes with time.

Numbers go in only after the derivative.

Careful: not A = π(5)² first ✗

3 Take the derivative

Both A and r change with time.

The chain rule: r squared gives 2r times dr/dt.

π just waits.

dAdt = 2πr drdt

4 Put the numbers in

Put in r = 5 and dr/dt = 2.

dAdt = 2π(5)(2)

5 Solve for the rate

Multiply the numbers: 20π.

= 20π cm²/s

With π ≈ 3.14159, about 62.83 cm² per second.

≈ 62.83 cm²/s

6 Check

Let's check: a tiny moment later, 0.001 seconds.

r is 5.002.

The area grows by about 0.06284.

r = 5.002: A grows by ≈ 0.06284

That is about 62.84 per second.

Right!

change ÷ 0.001 ≈ 62.84

Let's look back.

First: draw and name.

Then: write the equation.

Then: take the derivative.

Then: put the numbers in.

Then: solve for the rate.

Last: check.

Answer
≈ 62.83 cm²/s

Your turn

Try this one yourself, then check:

Show the answer
The area grows at 12π ≈ 37.70 cm²/s.

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