Step by step
The question
Question: The radius of a circle grows at 4 m/s.
How fast is the area growing when the radius is 6 m?
1 Draw and name
Draw it.
The radius r grows, so the area A grows too.
The radius grows by 4 m per second: dr/dt = 4.
dr/dt means how fast r changes: the change each second.
We want dA/dt at the moment when r = 6.
2 Write the equation
The area of a circle: A = π r squared.
Careful!
Do not put r = 6 in yet!
r changes with time.
Numbers go in only after the derivative.
3 Take the derivative
Both A and r change with time.
The chain rule: r squared gives 2r times dr/dt.
π just waits.
4 Put the numbers in
Put in r = 6 and dr/dt = 4.
5 Solve for the rate
Multiply the numbers: 48π.
With π ≈ 3.14159, about 150.80 m² per second.
6 Check
Let's check: a tiny moment later, 0.001 seconds.
r is 6.004.
The area grows by about 0.15085.
That is about 150.85 per second.
Right!
Let's look back.
First: draw and name.
Then: write the equation.
Then: take the derivative.
Then: put the numbers in.
Then: solve for the rate.
Last: check.