Steply

u = <3, 1>, v = <1, 2>, find 2u - v

Step by step, with the reason for every step · Adding, subtracting, × a number · Precalculus

Step by step

The question

Question: find 2u − v, when u = ⟨3, 1⟩ and v = ⟨1, 2⟩.

u = ⟨3, 1⟩ and v = ⟨1, 2⟩

1 Multiply by 2

2u is 2 times each part of u.

2u = ⟨2 × 3, 2 × 1⟩

So 2u = ⟨6, 2⟩.

2u = ⟨6, 2⟩

2 Draw tip to tail

Draw the grid.

Draw 2u from the origin.

Taking away v is adding −v: the arrow turned around.

Put the start of −v at the tip of 2u.

Tip to tail.

The answer goes from the very start to the very end.

3 Take away the parts

Take away the across parts, and the up parts.

Taking away an arrow turns it around, so its parts change sign.

2u − v = ⟨6 − 1, 2 − 2⟩

6 minus 1 is 5.

2 minus 2 is 0.

So 2u − v = ⟨5, 0⟩.

2u − v = ⟨5, 0⟩

4 Check

Let's check on the grid.

The red arrow ends at (5, 0).

That is right 5 from the start: ⟨5, 0⟩.

The same!

tip (5, 0) → ⟨5, 0⟩

Let's look back.

First: multiply by 2.

Then: draw tip to tail.

Then: take away the parts.

Last: check.

Answer
2u − v = ⟨5, 0⟩

Your turn

Try this one yourself, then check:

u = ⟨1, 1⟩, v = ⟨1, 2⟩: find 2u − v
Show the answer
2u − v = ⟨1, 0⟩

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