Steply

u = <-1, 2>, v = <2, 1>, find 3u + v

Step by step, with the reason for every step · Adding, subtracting, × a number · Precalculus

Step by step

The question

Question: find 3u + v, when u = ⟨−1, 2⟩ and v = ⟨2, 1⟩.

u = ⟨−1, 2⟩ and v = ⟨2, 1⟩

1 Multiply by 3

3u is 3 times each part of u.

3u = ⟨3 × (−1), 3 × 2⟩

So 3u = ⟨−3, 6⟩.

3u = ⟨−3, 6⟩

2 Draw tip to tail

Draw the grid.

Draw 3u from the origin.

Put the start of v at the tip of 3u.

Tip to tail.

The answer goes from the very start to the very end.

3 Add the parts

Add the across parts, and the up parts.

Each arrow adds its own across and up.

3u + v = ⟨−3 + 2, 6 + 1⟩

−3 plus 2 is −1.

6 plus 1 is 7.

So 3u + v = ⟨−1, 7⟩.

3u + v = ⟨−1, 7⟩

4 Check

Let's check on the grid.

The red arrow ends at (−1, 7).

That is left 1 and up 7 from the start: ⟨−1, 7⟩.

The same!

tip (−1, 7) → ⟨−1, 7⟩

Let's look back.

First: multiply by 3.

Then: draw tip to tail.

Then: add the parts.

Last: check.

Answer
3u + v = ⟨−1, 7⟩

Your turn

Try this one yourself, then check:

u = ⟨−2, 1⟩, v = ⟨1, 4⟩: find 3u + v
Show the answer
3u + v = ⟨−5, 7⟩

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