Steply

u = <4, 2>, v = <1, -1>, find u + 2v

Step by step, with the reason for every step · Adding, subtracting, × a number · Precalculus

Step by step

The question

Question: find u + 2v, when u = ⟨4, 2⟩ and v = ⟨1, −1⟩.

u = ⟨4, 2⟩ and v = ⟨1, −1⟩

1 Multiply by 2

2v is 2 times each part of v.

2v = ⟨2 × 1, 2 × (−1)⟩

So 2v = ⟨2, −2⟩.

2v = ⟨2, −2⟩

2 Draw tip to tail

Draw the grid.

Draw u from the origin.

Put the start of 2v at the tip of u.

Tip to tail.

The answer goes from the very start to the very end.

3 Add the parts

Add the across parts, and the up parts.

Each arrow adds its own across and up.

u + 2v = ⟨4 + 2, 2 + (−2)⟩

Adding a negative is the same as taking away.

+ (−) = −

4 plus 2 is 6.

2 plus (−2) is 0.

So u + 2v = ⟨6, 0⟩.

u + 2v = ⟨6, 0⟩

4 Check

Let's check on the grid.

The red arrow ends at (6, 0).

That is right 6 from the start: ⟨6, 0⟩.

The same!

tip (6, 0) → ⟨6, 0⟩

Let's look back.

First: multiply by 2.

Then: draw tip to tail.

Then: add the parts.

Last: check.

Answer
u + 2v = ⟨6, 0⟩

Your turn

Try this one yourself, then check:

u = ⟨1, 2⟩, v = ⟨4, −1⟩: find u + 2v
Show the answer
u + 2v = ⟨9, 0⟩

More from Adding, subtracting, × a number

The whole lesson: Adding, subtracting, × a number →