Steply

u = <2, -1>, v = <-1, 3>, find 2u + 3v

Step by step, with the reason for every step · Adding, subtracting, × a number · Precalculus

Step by step

The question

Question: find 2u + 3v, when u = ⟨2, −1⟩ and v = ⟨−1, 3⟩.

u = ⟨2, −1⟩ and v = ⟨−1, 3⟩

1 Multiply by 2

2u is 2 times each part of u.

2u = ⟨2 × 2, 2 × (−1)⟩

So 2u = ⟨4, −2⟩.

2u = ⟨4, −2⟩

2 Multiply by 3

3v is 3 times each part of v.

3v = ⟨3 × (−1), 3 × 3⟩

So 3v = ⟨−3, 9⟩.

3v = ⟨−3, 9⟩

3 Draw tip to tail

Draw the grid.

Draw 2u from the origin.

Put the start of 3v at the tip of 2u.

Tip to tail.

The answer goes from the very start to the very end.

4 Add the parts

Add the across parts, and the up parts.

Each arrow adds its own across and up.

2u + 3v = ⟨4 + (−3), −2 + 9⟩

Adding a negative is the same as taking away.

+ (−) = −

4 plus (−3) is 1.

−2 plus 9 is 7.

So 2u + 3v = ⟨1, 7⟩.

2u + 3v = ⟨1, 7⟩

5 Check

Let's check on the grid.

The red arrow ends at (1, 7).

That is right 1 and up 7 from the start: ⟨1, 7⟩.

The same!

tip (1, 7) → ⟨1, 7⟩

Let's look back.

First: multiply by 2.

Then: multiply by 3.

Then: draw tip to tail.

Then: add the parts.

Last: check.

Answer
2u + 3v = ⟨1, 7⟩

Your turn

Try this one yourself, then check:

u = ⟨3, −1⟩, v = ⟨−1, 1⟩: find 2u + 3v
Show the answer
2u + 3v = ⟨3, 1⟩

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