Steply

Use the divergence test on Σ 1/n

Step by step, with the reason for every step · The divergence test · Calculus 2

Step by step

The question

Question: decide if the series converges: the sum of 1/n for n from 1 to infinity.

Σn = 1∞1n =

1 The term

A series adds up the terms aₙ for ever.

First look at one term, 1 over n.

an = 1n

The divergence test: if the terms do not go to 0, adding them for ever never settles.

The series diverges.

divergence test:
if an does not → 0,
the series diverges

2 The limit

The bottom grows without end: the terms go to 0.

as n → ∞ = 1n → 0

3 Decide

The terms go to 0.

Then this test cannot tell: some series like this converge, some diverge.

= the test cannot tell

Careful!

Terms going to 0 is not enough!

The sum of 1/n has terms going to 0, but it diverges.

Careful: not an → 0, so the series converges ✗

Two series, both with terms going to 0: one diverges and one converges.

Another test must decide: the integral test is next.

Σ 1/n: terms → 0, diverges
Σ 1/n²: terms → 0, converges

4 Check

Let's look with a calculator: the partial sums of the first 10, 100 and 1000 terms are 2.93, 5.19, 7.49.

Hard to tell from these alone: that is why we need another test.

Right!

S₁₀ ≈ 2.93, S₁₀₀ ≈ 5.19, S₁₀₀₀ ≈ 7.49

Let's look back.

First: the term.

Then: the limit.

Then: decide.

Last: check.

Answer
= the test cannot tell

More from The divergence test

The whole lesson: The divergence test →