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Vector from (0, 0) to (3, 4)

Step by step, with the reason for every step · Vector from two points / magnitude · Precalculus

Step by step

The question

Question: find the vector from (0, 0) to (3, 4), and its length.

(0, 0) to (3, 4)

1 Draw the arrow

Draw the grid.

The arrow starts at (0, 0)

and ends at (3, 4).

Draw the arrow from the start to the end.

We call it v.

2 Count across and up

Across: from x = 0 to x = 3 is right 3.

Up: from y = 0 to y = 4 is up 4.

A vector is written with its two parts: across, then up.

Each part is end minus start.

v = ⟨3 − 0, 4 − 0⟩
end − start

Careful!

Not start minus end.

That gives ⟨−3, −4⟩: an arrow pointing the other way.

Careful: not ⟨0 − 3, 0 − 4⟩ ✗

3 minus 0 is 3.

4 minus 0 is 4.

So v = ⟨3, 4⟩.

v = ⟨3, 4⟩

3 Find the length

Across and up make a right angle.

The arrow is the longest side.

The length ‖v‖: the long side of the right triangle.

Pythagoras: square the two parts, add them, then take the square root.

‖v‖ = √32 + 42

3² is 3 times 3: 9.

32 = 3 × 3 = 9

4² is 16.

42 = 4 × 4 = 16

Write the squares: 9 + 16.

‖v‖ = √9 + 16

9 plus 16 is 25.

‖v‖ = √25

5 times 5 is 25.

5 × 5 = 25

So ‖v‖ = 5.

‖v‖ = 5

4 Check

Let's check: start at (0, 0) and add the parts.

We land on (3, 4), the end!

(0 + 3, 0 + 4) = (3, 4)

And the length.

Square the length: we get 25.

The same as 9 plus 16.

Right!

5 × 5 = 25 and 9 + 16 = 25

Let's look back.

First: draw the arrow.

Then: count across and up.

Then: find the length.

Last: check.

Answer
v = ⟨3, 4⟩

Your turn

Try this one yourself, then check:

Find the vector from (0, 0) to (4, 3)
Show the answer
⟨4, 3⟩, ‖v‖ = 5

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