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Vector from two points / magnitude

Precalculus ยท 23 problems, easy to harder

โ–ถ Watch the first one solved

How we do it

  1. Draw the arrow
  2. Count across and up
  3. Find the length
  4. Check

The steps for Vector from (1, 2) to (4, 6). Every solution names its steps, so you always know what comes next.

Worked examples

Vector from (1, 2) to (4, 6) Easy

The question

Question: find the vector from (1, 2) to (4, 6), and its length.

(1, 2) to (4, 6)

1 Draw the arrow

Draw the grid.

The arrow starts at (1, 2)

and ends at (4, 6).

Draw the arrow from the start to the end.

We call it v.

2 Count across and up

Across: from x = 1 to x = 4 is right 3.

Up: from y = 2 to y = 6 is up 4.

A vector is written with its two parts: across, then up.

Each part is end minus start.

v = โŸจ4 โˆ’ 1, 6 โˆ’ 2โŸฉ
end โˆ’ start

Careful!

Not start minus end.

That gives โŸจโˆ’3, โˆ’4โŸฉ: an arrow pointing the other way.

Careful: not โŸจ1 โˆ’ 4, 2 โˆ’ 6โŸฉ โœ—

4 minus 1 is 3.

6 minus 2 is 4.

So v = โŸจ3, 4โŸฉ.

v = โŸจ3, 4โŸฉ

3 Find the length

Across and up make a right angle.

The arrow is the longest side.

The length โ€–vโ€–: the long side of the right triangle.

Pythagoras: square the two parts, add them, then take the square root.

โ€–vโ€– = โˆš32 + 42

3ยฒ is 3 times 3: 9.

32 = 3 ร— 3 = 9

4ยฒ is 16.

42 = 4 ร— 4 = 16

Write the squares: 9 + 16.

โ€–vโ€– = โˆš9 + 16

9 plus 16 is 25.

โ€–vโ€– = โˆš25

5 times 5 is 25.

5 ร— 5 = 25

So โ€–vโ€– = 5.

โ€–vโ€– = 5

4 Check

Let's check: start at (1, 2) and add the parts.

We land on (4, 6), the end!

(1 + 3, 2 + 4) = (4, 6)

And the length.

Square the length: we get 25.

The same as 9 plus 16.

Right!

5 ร— 5 = 25 and 9 + 16 = 25

Let's look back.

First: draw the arrow.

Then: count across and up.

Then: find the length.

Last: check.

Answer
v = โŸจ3, 4โŸฉ

โ–ถ Watch it solved

Vector from (3, 5) to (0, 1) Medium

The question

Question: find the vector from (3, 5) to (0, 1), and its length.

(3, 5) to (0, 1)

1 Draw the arrow

Draw the grid.

The arrow starts at (3, 5)

and ends at (0, 1).

Draw the arrow from the start to the end.

We call it v.

2 Count across and up

Across: from x = 3 to x = 0 is left 3.

Down: from y = 5 to y = 1 is down 4.

A vector is written with its two parts: across, then up.

Each part is end minus start.

v = โŸจ0 โˆ’ 3, 1 โˆ’ 5โŸฉ
end โˆ’ start

Careful!

Not start minus end.

That gives โŸจ3, 4โŸฉ: an arrow pointing the other way.

Careful: not โŸจ3 โˆ’ 0, 5 โˆ’ 1โŸฉ โœ—

0 minus 3 is โˆ’3.

1 minus 5 is โˆ’4.

So v = โŸจโˆ’3, โˆ’4โŸฉ.

A minus means left or down.

v = โŸจโˆ’3, โˆ’4โŸฉ

3 Find the length

Across and down make a right angle.

The arrow is the longest side.

The length โ€–vโ€–: the long side of the right triangle.

Pythagoras: square the two parts, add them, then take the square root.

โ€–vโ€– = โˆš(โˆ’3)2 + (โˆ’4)2

(โˆ’3)ยฒ is (โˆ’3) times (โˆ’3): 9.

Minus times minus is plus.

(โˆ’3)2 = (โˆ’3) ร— (โˆ’3) = 9

(โˆ’4)ยฒ is 16.

(โˆ’4)2 = (โˆ’4) ร— (โˆ’4) = 16

Write the squares: 9 + 16.

โ€–vโ€– = โˆš9 + 16

9 plus 16 is 25.

โ€–vโ€– = โˆš25

5 times 5 is 25.

5 ร— 5 = 25

So โ€–vโ€– = 5.

โ€–vโ€– = 5

4 Check

Let's check: start at (3, 5) and add the parts.

We land on (0, 1), the end!

(3 + (โˆ’3), 5 + (โˆ’4)) = (0, 1)

And the length.

Square the length: we get 25.

The same as 9 plus 16.

Right!

5 ร— 5 = 25 and 9 + 16 = 25

Let's look back.

First: draw the arrow.

Then: count across and up.

Then: find the length.

Last: check.

Answer
v = โŸจโˆ’3, โˆ’4โŸฉ

โ–ถ Watch it solved

Vector from (1, 1) to (4, 4) Harder

The question

Question: find the vector from (1, 1) to (4, 4), and its length.

(1, 1) to (4, 4)

1 Draw the arrow

Draw the grid.

The arrow starts at (1, 1)

and ends at (4, 4).

Draw the arrow from the start to the end.

We call it v.

2 Count across and up

Across: from x = 1 to x = 4 is right 3.

Up: from y = 1 to y = 4 is up 3.

A vector is written with its two parts: across, then up.

Each part is end minus start.

v = โŸจ4 โˆ’ 1, 4 โˆ’ 1โŸฉ
end โˆ’ start

Careful!

Not start minus end.

That gives โŸจโˆ’3, โˆ’3โŸฉ: an arrow pointing the other way.

Careful: not โŸจ1 โˆ’ 4, 1 โˆ’ 4โŸฉ โœ—

4 minus 1 is 3.

4 minus 1 is 3.

So v = โŸจ3, 3โŸฉ.

v = โŸจ3, 3โŸฉ

3 Find the length

Across and up make a right angle.

The arrow is the longest side.

The length โ€–vโ€–: the long side of the right triangle.

Pythagoras: square the two parts, add them, then take the square root.

โ€–vโ€– = โˆš32 + 32

3ยฒ is 3 times 3: 9.

32 = 3 ร— 3 = 9

Write the squares: 9 + 9.

โ€–vโ€– = โˆš9 + 9

9 plus 9 is 18.

โ€–vโ€– = โˆš18

But 18 has a square number in it: 9.

18 is 9 times 2.

โ€–vโ€– = โˆš9 ร— 2

A root of a times splits into two roots.

โ€–vโ€– = โˆš9 ร— โˆš2

โˆš9 is 3.

3 ร— 3 = 9

So โ€–vโ€– = 3โˆš2.

That is the exact answer, made simple.

โ€–vโ€– = 3โˆš2

4 Check

Let's check: start at (1, 1) and add the parts.

We land on (4, 4), the end!

(1 + 3, 1 + 3) = (4, 4)

And the length.

Square the length: we get 18.

The same as 9 plus 9.

Right!

(3โˆš2)ยฒ = 9 ร— 2 = 18 and 9 + 9 = 18

Let's look back.

First: draw the arrow.

Then: count across and up.

Then: find the length.

Last: check.

Answer
v = โŸจ3, 3โŸฉ

โ–ถ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. vector from (1, 2) to (4, 6)
    Answer
    v = โŸจ3, 4โŸฉ
  2. vector from (0, 0) to (3, 4)
    Answer
    v = โŸจ3, 4โŸฉ
  3. vector from (2, 1) to (8, 9)
    Answer
    v = โŸจ6, 8โŸฉ
  4. vector from (1, 1) to (1, 6)
    Answer
    v = โŸจ0, 5โŸฉ
  5. vector from (2, 3) to (7, 3)
    Answer
    v = โŸจ5, 0โŸฉ
  6. magnitude of <3, 4>
    Answer
    Careful: not โ€–vโ€– = 3 + 4 = 7 โœ—
  7. magnitude of <6, 8>
    Answer
    Careful: not โ€–vโ€– = 6 + 8 = 14 โœ—
  8. magnitude of <0, -5>
    Answer
    โ€–vโ€– = 5

Medium

  1. vector from (3, 5) to (0, 1)
    Answer
    v = โŸจโˆ’3, โˆ’4โŸฉ
  2. vector from (-2, 1) to (2, -2)
    Answer
    v = โŸจ4, โˆ’3โŸฉ
  3. vector from (4, -6) to (-1, 6)
    Answer
    v = โŸจโˆ’5, 12โŸฉ
  4. magnitude of <3, -4>
    Answer
    Careful: not โ€–vโ€– = 3 + 4 = 7 โœ—
  5. magnitude of <-12, 5>
    Answer
    Careful: not โ€–vโ€– = 12 + 5 = 17 โœ—
  6. magnitude of <-6, -8>
    Answer
    Careful: not โ€–vโ€– = 6 + 8 = 14 โœ—
  7. vector from (-3, -2) to (3, 6)
    Answer
    v = โŸจ6, 8โŸฉ
  8. magnitude of <-8, 6>
    Answer
    Careful: not โ€–vโ€– = 8 + 6 = 14 โœ—

Harder

  1. vector from (1, 1) to (4, 4)
    Answer
    v = โŸจ3, 3โŸฉ
  2. vector from (-2, 3) to (2, -1)
    Answer
    v = โŸจ4, โˆ’4โŸฉ
  3. magnitude of <2, 4>
    Answer
    Careful: not โ€–vโ€– = 2 + 4 = 6 โœ—
  4. magnitude of <-1, 3>
    Answer
    Careful: not โ€–vโ€– = 1 + 3 = 4 โœ—
  5. vector from (0, -2) to (5, 0)
    Answer
    v = โŸจ5, 2โŸฉ
  6. magnitude of <6, -3>
    Answer
    Careful: not โ€–vโ€– = 6 + 3 = 9 โœ—
  7. vector from (-1, -1) to (1, 5)
    Answer
    v = โŸจ2, 6โŸฉ