Steply

Where is f(x) = x^3 - 3x^2 increasing

Step by step, with the reason for every step · Maximum, minimum and optimization · Calculus

Step by step

The question

Question: find where f(x) = x³ − 3x² is increasing and where it is decreasing.

f(x) = x3 − 3x2

The derivative is the slope.

Where it is positive, the graph goes up.

Where it is negative, the graph goes down.

f′(x) > 0: going up ↗
f′(x) < 0: going down ↘

1 Find f′(x)

Use the power rule on each term.

f′(x) = 3x^(3 − 1) − 3 × 2x^(2 − 1)

Now we have f′(x) = 3x² − 6x.

= 3x2 − 6x

2 Solve f′(x) = 0

At a turning point the graph is flat for a moment: the slope is 0.

So we solve f′(x) = 0.

f′(x) = 0
3x2 − 6x = 0

Take out the 3.

3(x2 − 2x) = 0

We need two numbers that multiply to 0 and add to −2: 0 and −2.

3x(x − 2) = 0
0 × (−2) = 0, 0 + (−2) = −2

A product is 0 only when one of its parts is 0.

a × b = 0 → a = 0 or b = 0

So x = 0 or x = 2.

x = 0 or x = 2

Careful!

f′ = 0 alone does not tell max or min.

The signs on each side tell us.

Careful: f′(x) = 0 is not enough: look at the signs

3 Sign table

A sign table.

The numbers 0 and 2 cut the line into 3 parts.

Test one number in each part: −1, 1, 3.

f′(−1) = 9, f′(1) = −3, f′(3) = 9

f′(−1) is 9: positive.

So f goes up there.

f′(1) is −3: negative.

So f goes down there.

f′(3) is 9: positive.

So f goes up there.

0
0

4 Read the table

f is increasing, going up, where f′ is positive: x < 0 and x > 2.

up ↗ : x < 0 and x > 2

f is decreasing, going down, where f′ is negative: 0 < x < 2.

down ↘ : 0 < x < 2

5 Check

Let's check with the graph.

Up, then down, then up: just like the table.

Right!

Let's look back.

First: find f′(x).

Then: solve f′(x) = 0.

Then: sign table.

Then: read the table.

Last: check.

Answer
up ↗ : x < 0 and x > 2

Your turn

Try this one yourself, then check:

Find where f(x) = x3 − 6x2 + 9x + 2
Show the answer
increasing: x < 1 and x > 3; decreasing: 1 < x < 3

More from Maximum, minimum and optimization

The whole lesson: Maximum, minimum and optimization →