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Where is f(x) = x^2 + 4x increasing

Step by step, with the reason for every step · Maximum, minimum and optimization · Calculus

Step by step

The question

Question: find where f(x) = x² + 4x is increasing and where it is decreasing.

f(x) = x2 + 4x

The derivative is the slope.

Where it is positive, the graph goes up.

Where it is negative, the graph goes down.

f′(x) > 0: going up ↗
f′(x) < 0: going down ↘

1 Find f′(x)

Use the power rule on each term.

f′(x) = 2x^(2 − 1) + 4 × 1

Now we have f′(x) = 2x + 4.

= 2x + 4

2 Solve f′(x) = 0

At a turning point the graph is flat for a moment: the slope is 0.

So we solve f′(x) = 0.

f′(x) = 0
2x + 4 = 0

Take out the 2.

2(x + 2) = 0

So x = −2.

x = −2

Careful!

f′ = 0 alone does not tell max or min.

The signs on each side tell us.

Careful: f′(x) = 0 is not enough: look at the signs

3 Sign table

A sign table.

The numbers −2 cut the line into 2 parts.

Test one number in each part: −3, −1.

f′(−3) = −2, f′(−1) = 2

f′(−3) is −2: negative.

So f goes down there.

f′(−1) is 2: positive.

So f goes up there.

0

4 Read the table

f is increasing, going up, where f′ is positive: x > −2.

up ↗ : x > −2

f is decreasing, going down, where f′ is negative: x < −2.

down ↘ : x < −2

5 Check

Let's check with the graph.

Down, then up: just like the table.

Right!

Let's look back.

First: find f′(x).

Then: solve f′(x) = 0.

Then: sign table.

Then: read the table.

Last: check.

Answer
up ↗ : x > −2

Your turn

Try this one yourself, then check:

Find where f(x) = x2 − 2x + 1
Show the answer
increasing: x > 1; decreasing: x < 1

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