Step by step
The question
Question: write gcd(84, 36) as 84x + 36y, with whole numbers x and y.
1 Divide the bigger by the smaller
Divide the bigger number by the smaller: 36 goes into 84 2 times, and 12 is left over.
Here is the trick.
A number that goes into 84 and 36 also goes into 12, because 12 is 84 minus 2 × 36.
So the gcd does not change, and the numbers get smaller.
2 Keep going
Now the same with 36 and 12: the divisor moves left, the remainder becomes the new divisor.
3 The last remainder before 0
Careful!
0 only tells us to stop.
The answer is the last remainder before it: 12.
The last remainder that is not 0 is 12.
So gcd(84, 36) = 12.
4 Go back up
Start from the second last row, written for 12: 12 = 84 − 2 × 36.
So x = 1 and y = −2.
5 Check
Put them in: 84 × 1 plus 36 × (−2) is 12.
Right!
Let's look back.
First: divide the bigger by the smaller.
Then: keep going.
Then: the last remainder before 0.
Then: go back up.
Last: check.