Step by step
The question
Question: graph 2x + y > 2 and x − y < 1.
We shade the answer of each one.
Where both are shaded, both are true.
1 Crossing points of ①
On the x-axis, y = 0.
Put 0 in place of y.
Adding 0 changes nothing.
2x means 2 times x.
We want just x.
To remove times 2, we divide by 2.
We do it on both sides, so they stay equal.
2 divided by 2 is 1.
So just x is left.
2 divided by 2 is 1.
So x = 1.
On the y-axis, x = 0.
Put 0 in place of x.
2 times 0 is 0.
0 plus y is just y.
So y = 2.
So line ① crosses the axes at (1, 0) and (0, 2).
2 Crossing points of ②
On the x-axis, y = 0.
Put 0 in place of y.
1 times 0 is 0.
Taking away 0 changes nothing.
So x = 1.
On the y-axis, x = 0.
Put 0 in place of x.
0 minus y is −y.
−y means −1 times y.
We want just y.
To remove times −1, we divide by −1.
We do it on both sides, so they stay equal.
−1 divided by −1 is 1.
So just y is left.
Plus over minus is minus.
1 divided by −1 is −1.
So y = −1.
So line ② crosses the axes at (1, 0) and (0, −1).
3 Graph ①
Draw the grid.
①: The sign is more than, with no "or equal to".
So the line is dashed.
Put the two crossing points on the grid,
and join them: dashed.
Which side?
We test one point: (0, 0).
Put x = 0 and y = 0 into ①.
Is 0 more than 2?
No, false.
So we shade the other side, away from (0, 0), in red.
4 Graph ②
②: The sign is less than, with no "or equal to".
So the line is dashed.
Put the two crossing points on the grid,
and join them: dashed.
Which side?
We test one point: (0, 0).
Put x = 0 and y = 0 into ②.
Is 0 less than 1?
Yes, true.
Careful!
The sign alone does not say above or below.
When y has a minus in front, it can turn.
The test point tells us.
So we shade the side with (0, 0), in blue.
5 Where both are shaded
This part is shaded twice.
It is the answer.
6 Check
Let's check with a point in the purple part: (1, 1).
Put it into ①.
Now ②.
True in both!
So the answer is right.
Let's look back.
First: crossing points of ①.
Then: crossing points of ②.
Then: graph ①.
Then: graph ②.
Then: where both are shaded.
Last: check.