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Slope fields

Differential Equations ยท 20 problems, easy to harder

โ–ถ Watch the first one solved

How we do it

  1. The idea
  2. Slopes at some points
  3. Draw the slope lines
  4. Follow the slopes
  5. Read the picture
  6. Check

The steps for Slope field of dy/dx = xy and the solution through (0, 1). Every solution names its steps, so you always know what comes next.

Worked examples

Slope field of dy/dx = x Easy

The question

Question: draw the slope field of dy/dx = x.

dydx = x

1 The idea

dy/dx is the slope of a solution curve.

For each point x, y, the equation tells us that slope.

So we draw a short line with that slope at each point: a slope field.

dy/dx = the slope of the solution at (x, y)
slope field: a short line with that slope at each point

2 Slopes at some points

Put x and y of each point into x.

At (0, 0): 0 = 0.

slope at (0, 0) = 0 = 0

At (1, 0): 1 = 1.

slope at (1, 0) = 1 = 1

Careful!

x comes first, then y.

At (1, 0), x is 1 and y is 0.

Careful: not at (1, 0): 0 = 0 โœ—
slope at (โˆ’1, 1) = (โˆ’1) = โˆ’1

3 Draw the slope lines

Now the grid.

The slopes we found: a short purple line at each point.

Slope 0 is flat, slope 1 goes up like a hill, a minus slope goes down.

The same at every point of the grid.

This is the slope field.

4 Read the picture

slope 0 where x = 0: x = 0

The lines are flat where x = 0: on the upright line x = 0.

Every line in a column has the same slope: y does not change it.

Any solution curve follows these lines.

5 Check

Let's check one more point, (2, โˆ’1): the slope is 2.

Its line on the grid goes up, steeply.

Right!

slope at (2, โˆ’1) = 2 = 2

Let's look back.

First: the idea.

Then: slopes at some points.

Then: draw the slope lines.

Then: read the picture.

Last: check.

Answer
slope at (โˆ’1, 1) = (โˆ’1) = โˆ’1

โ–ถ Watch it solved

Slope field of dy/dx = -x Medium

The question

Question: draw the slope field of dy/dx = โˆ’x.

dydx = โˆ’x

1 The idea

dy/dx is the slope of a solution curve.

For each point x, y, the equation tells us that slope.

So we draw a short line with that slope at each point: a slope field.

dy/dx = the slope of the solution at (x, y)
slope field: a short line with that slope at each point

2 Slopes at some points

Put x and y of each point into โˆ’x.

At (0, 0): 0 = 0.

slope at (0, 0) = 0 = 0

At (1, 0): โˆ’1 = โˆ’1.

slope at (1, 0) = โˆ’1 = โˆ’1

Careful!

x comes first, then y.

At (1, 0), x is 1 and y is 0.

Careful: not at (1, 0): 0 = 0 โœ—
slope at (โˆ’1, 1) = โˆ’(โˆ’1) = 1

3 Draw the slope lines

Now the grid.

The slopes we found: a short purple line at each point.

Slope 0 is flat, slope 1 goes up like a hill, a minus slope goes down.

The same at every point of the grid.

This is the slope field.

4 Read the picture

slope 0 where โˆ’x = 0: x = 0

The lines are flat where โˆ’x = 0: on the upright line x = 0.

Every line in a column has the same slope: y does not change it.

Any solution curve follows these lines.

5 Check

Let's check one more point, (2, โˆ’1): the slope is โˆ’2.

Its line on the grid goes down, steeply.

Right!

slope at (2, โˆ’1) = โˆ’2 = โˆ’2

Let's look back.

First: the idea.

Then: slopes at some points.

Then: draw the slope lines.

Then: read the picture.

Last: check.

Answer
slope at (โˆ’1, 1) = โˆ’(โˆ’1) = 1

โ–ถ Watch it solved

Slope field of dy/dx = xy and the solution through (0, 1) Harder

The question

Question: draw the slope field of dy/dx = xy, and the solution through (0, 1).

dydx = xy

1 The idea

dy/dx is the slope of a solution curve.

For each point x, y, the equation tells us that slope.

So we draw a short line with that slope at each point: a slope field.

dy/dx = the slope of the solution at (x, y)
slope field: a short line with that slope at each point

2 Slopes at some points

Put x and y of each point into xy.

At (0, 0): 0 ร— 0 = 0.

slope at (0, 0) = 0 ร— 0 = 0

At (1, 1): 1 ร— 1 = 1.

slope at (1, 1) = 1 ร— 1 = 1
slope at (โˆ’1, 1) = (โˆ’1) ร— 1 = โˆ’1

Careful!

A point is x first, then y.

Put each one in its own place.

Careful: (x, y): x first, then y

3 Draw the slope lines

Now the grid.

The slopes we found: a short purple line at each point.

Slope 0 is flat, slope 1 goes up like a hill, a minus slope goes down.

The same at every point of the grid.

This is the slope field.

4 Follow the slopes

Start at (0, 1).

Now follow the little lines, like a leaf on a river.

This red curve is the solution through (0, 1).

5 Read the picture

slope 0 where xy = 0: on the x-axis and the y-axis

The lines are flat where xy = 0: on the x-axis and on the y-axis.

Every solution follows the field, like the red one.

6 Check

Let's check one more point, (2, โˆ’1): the slope is โˆ’2.

Its line on the grid goes down, steeply.

Right!

slope at (2, โˆ’1) = 2 ร— (โˆ’1) = โˆ’2

Let's look back.

First: the idea.

Then: slopes at some points.

Then: draw the slope lines.

Then: follow the slopes.

Then: read the picture.

Last: check.

Answer
slope at (โˆ’1, 1) = (โˆ’1) ร— 1 = โˆ’1

โ–ถ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. slope field of dy/dx = x
    Answer
    slope at (โˆ’1, 1) = (โˆ’1) = โˆ’1
  2. slope field of dy/dx = y
    Answer
    slope at (1, โˆ’1) = (โˆ’1) = โˆ’1
  3. slope field of dy/dx = x + y
    Answer
    slope at (1, 1) = 1 + 1 = 2
  4. slope field of dy/dx = x - y
    Answer
    slope at (0, 1) = 0 โˆ’ 1 = โˆ’1
  5. slope field of dy/dx = -y
    Answer
    slope at (1, โˆ’1) = โˆ’(โˆ’1) = 1
  6. slope field of dy/dx = 2x - 2
    Answer
    slope at (โˆ’1, 1) = 2 ร— (โˆ’1) โˆ’ 2 = โˆ’4
  7. slope field of dy/dx = y - 1
    Answer
    slope at (1, โˆ’1) = (โˆ’1) โˆ’ 1 = โˆ’2

Medium

  1. slope field of dy/dx = -x
    Answer
    slope at (โˆ’1, 1) = โˆ’(โˆ’1) = 1
  2. slope field of dy/dx = x + y and the solution through (0, 1)
    Answer
    slope at (1, 1) = 1 + 1 = 2
  3. slope field of dy/dx = x - y and the solution through (0, 1)
    Answer
    slope at (0, 1) = 0 โˆ’ 1 = โˆ’1
  4. slope field of dy/dx = y and the solution through (0, 1)
    Answer
    slope at (1, โˆ’1) = (โˆ’1) = โˆ’1
  5. slope field of dy/dx = -y and the solution through (0, 2)
    Answer
    slope at (1, โˆ’1) = โˆ’(โˆ’1) = 1
  6. slope field of dy/dx = x and the solution through (0, -1)
    Answer
    slope at (โˆ’1, 1) = (โˆ’1) = โˆ’1
  7. slope field of dy/dx = 2 - y and the solution through (0, 0)
    Answer
    slope at (1, โˆ’1) = โˆ’(โˆ’1) + 2 = 3

Harder

  1. slope field of dy/dx = xy and the solution through (0, 1)
    Answer
    slope at (โˆ’1, 1) = (โˆ’1) ร— 1 = โˆ’1
  2. slope field of dy/dx = -2xy and the solution through (0, 2)
    Answer
    slope at (โˆ’1, 1) = โˆ’2 ร— (โˆ’1) ร— 1 = 2
  3. slope field of dy/dx = x + 2y
    Answer
    slope at (0, 1) = 0 + 2 ร— 1 = 2
  4. slope field of dy/dx = y - x and the solution through (0, 2)
    Answer
    slope at (0, 1) = 0 + 1 = 1
  5. slope field of dy/dx = -x - y and the solution through (1, 1)
    Answer
    slope at (1, 1) = โˆ’1 โˆ’ 1 = โˆ’2
  6. slope field of dy/dx = 1 - x and the solution through (0, -2)
    Answer
    slope at (โˆ’1, 1) = โˆ’(โˆ’1) + 1 = 2