Step by step
The question
Question: find the vector from (−1, −1) to (1, 5), and its length.
1 Draw the arrow
Draw the grid.
The arrow starts at (−1, −1)
and ends at (1, 5).
Draw the arrow from the start to the end.
We call it v.
2 Count across and up
Across: from x = −1 to x = 1 is right 2.
Up: from y = −1 to y = 5 is up 6.
A vector is written with its two parts: across, then up.
Each part is end minus start.
Careful!
Not start minus end.
That gives ⟨−2, −6⟩: an arrow pointing the other way.
1 minus (−1) is 2.
5 minus (−1) is 6.
So v = ⟨2, 6⟩.
3 Find the length
Across and up make a right angle.
The arrow is the longest side.
The length ‖v‖: the long side of the right triangle.
Pythagoras: square the two parts, add them, then take the square root.
2² is 2 times 2: 4.
6² is 36.
Write the squares: 4 + 36.
4 plus 36 is 40.
But 40 has a square number in it: 4.
40 is 4 times 10.
A root of a times splits into two roots.
√4 is 2.
So ‖v‖ = 2√10.
That is the exact answer, made simple.
4 Check
Let's check: start at (−1, −1) and add the parts.
We land on (1, 5), the end!
And the length.
Square the length: we get 40.
The same as 4 plus 36.
Right!
Let's look back.
First: draw the arrow.
Then: count across and up.
Then: find the length.
Last: check.