Steply

a_1 = 5, a_n = a_(n-1) + 4, write the explicit rule

Step by step, with the reason for every step · Recursive sequences · Algebra 2

Step by step

The question

Question: a₁ = 5 and aₙ = aₙ₋₁ + 4.

Write the explicit rule: aₙ with n in it.

a1 = 5, an = an−1 + 4

aₙ₋₁ means the term just before aₙ.

A rule that makes each term from the term before is called recursive.

an−1 = the term before an

1 Read the rule

The first terms: 5, 9, 13.

= 5, 9, 13, ...

We add the same number every time.

So it is arithmetic, with d = 4.

+ 4 every time: arithmetic, d = 4

2 Write the explicit rule

The rule from the sequences lesson: the first term, plus (n − 1) times the difference.

an = a1 + (n − 1) × d

Careful!

Not 4n plus the start.

Term 1 adds no jumps yet, so we add d only n − 1 times.

Careful: not an = 4n + 5 ✗

Put in a₁ = 5 and d = 4.

an = 5 + (n − 1) × 4

The bracket is times 4.

n times 4 is 4n.

−1 times 4 is −4.

an = 5 + 4n − 4

Plain numbers go together: 5 − 4 is 1.

So aₙ = 4n + 1.

an = 4n + 1

3 Check

Let's check with term 3.

The recursive rule gave 13.

recursive: a3 = 13

The explicit rule with n = 3 gives 13 too.

It works!

explicit: a3 = 4(3) + 1 = 13

Let's look back.

First: read the rule.

Then: write the explicit rule.

Last: check.

Answer
an = 4n + 1

Your turn

Try this one yourself, then check:

a1 = 5, an = an−1 + 2, explicit rule?
Show the answer
an = 2n + 3

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