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A rectangle has an area of 100 cm². Find the smallest perimeter.

Step by step, with the reason for every step · Optimization · Calculus 1

Step by step

The question

Question: A rectangle has an area of 100 cm².

Find the smallest perimeter.

1 Draw and name

Call the sides x and y.

x = one side
y = the other side

2 Write the perimeter

The perimeter is two x sides and two y sides.

P = 2x + 2y

3 Use only one letter

Two letters.

The area gives the link: x times y is 100.

xy = 100

So y = 100 over x.

y = 100x

Put it in place of y.

P = 2x + 2 × 100x

Now we have P = 2x + 200 over x.

= 2x + 200x

4 Which x make sense

A length is positive: x is more than 0.

x > 0 =

5 Slope = 0

The smallest value is where the slope is 0.

2x gives 2.

200/x is 200x to the power −1, which gives −200/x².

P′(x) = 2 − 200x2
200x = 200x−1 → −200x−2

Set it to 0, and move the fraction across.

200x2 = 2

Times both sides by x², so they stay equal.

200 = 2x2

Divide by 2.

x2 = 100

x squared is 100, so x is 10.

Minus 10 squared is also 100, but x must be positive.

x = 10 (not −10)

Careful!

A length cannot be negative.

Only x = 10 is allowed.

Careful: not x = −10 ✗

6 Make sure it is the smallest

Before 10, the slope is negative: going down.

After it, positive: going up.

Down, then up: the bottom.

A minimum.

P′(9) = −0.47 < 0 ↘, P′(11) = 0.35 > 0 ↗

7 Answer the question

The other side: 100/10 is 10.

y = 10010 = 10

So the smallest perimeter is 40 cm.

The rectangle is a square!

P(10) = 2 × 10 + 2 × 10 = 40 cm

8 Check

Let's check with x a bit smaller: 9 gives 40.22.

x = 9: P = 40.22

And x = 11 gives 40.18.

Both are bigger than 40.

Right!

x = 11: P = 40.18

Let's look back.

First: draw and name.

Then: write the perimeter.

Then: use only one letter.

Then: which x make sense.

Then: slope = 0.

Then: make sure it is the smallest.

Then: answer the question.

Last: check.

Answer
P(10) = 2 × 10 + 2 × 10 = 40 cm

Your turn

Try this one yourself, then check:

Show the answer
smallest perimeter = 12 cm

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