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A ship sails 20 km on a bearing of 248°, how far south and how far…

Step by step, with the reason for every step · Bearings with trigonometry and Pythagoras · Geometry

Step by step

The question

Question: a ship goes 20 km on a bearing of 248°: how far south and how far west is it from the start?

1 Draw the triangle

Go straight south first, then straight west: a right triangle.

The path is the long side.

In the triangle we need the angle at the start, between the path and the south line: 68°.

angle with the north-south line = 248° − 180° = 68°

Careful!

The south side is next to the angle, so it uses cos.

The west side is across from it, so it uses sin.

Careful: south: next to the angle → cos; west: across → sin

2 How far south

cos is adjacent over hypotenuse.

So the south side is 20 times cos 68°: about 7.5 km.

south = 20 × cos 68° ≈ 7.5 km

3 How far west

sin is opposite over hypotenuse.

So the west side is 20 times sin 68°: about 18.5 km.

west = 20 × sin 68° ≈ 18.5 km

4 Check

Let's check with Pythagoras: the two legs squared add up to about 400, the path squared.

So it is right!

7.5² + 18.5² ≈ 398.5 ≈ 20² = 400

Let's look back.

First: draw the triangle.

Then: how far south.

Then: how far west.

Last: check.

Answer
west = 20 × sin 68° ≈ 18.5 km

Your turn

Try this one yourself, then check:

How far south and how far west?
Show the answer
3.1 km south, 8.5 km west

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