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A substance has a half-life of 3 years. How much of 90 g is left…

Step by step, with the reason for every step · Half-life and time with logs · Algebra 2

Step by step

The question

Question: A substance has a half-life of 3 years.

How much of 90 g is left after 10 years?

1 Count the half-lives

Every 3 years, half is left.

Half means times 1/2.

every 3 years: × 12

How many half-lives in 10 years?

10 divided by 3: 3.333333.

half-lives = 103 = 3.3333

2 Halve it that many times

A = the start times (1/2) to the power 3.333333.

A = 90 × (12)3.333333

The power is not whole.

With a calculator, (1/2) to the power 3.333333 is about 0.0992126.

(12)3.333333 ≈ 0.0992126

Times 90.

A ≈ 90 × 0.0992126

That is about 8.93 g, to two decimal places.

A ≈ 8.93 g

3 Check

Let's check if it makes sense.

3 half-lives leave 11.25 g.

4 half-lives leave 5.625 g.

3 half-lives: 11.25 g, 4 half-lives: 5.625 g

3.333333 is between 3 and 4, and our answer is between them too.

It works!

5.625 < 8.93 < 11.25

Let's look back.

First: count the half-lives.

Then: halve it that many times.

Last: check.

Answer
A ≈ 8.93 g

Your turn

Try this one yourself, then check:

Show the answer
≈ 20.75 g

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