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An open box with a square base must hold 500 cm³. Find the least…

Step by step, with the reason for every step · Optimization · Calculus 1

Step by step

The question

Question: An open box with a square base must hold 500 cm³.

Find the least material needed.

1 Draw and name

The base is a square: x by x.

The height is h.

There is no top.

x = the side of the base
h = the height

2 Write the material

The material is the base, x squared, plus 4 sides, each x by h.

S = x2 + 4xh

3 Use only one letter

S has two letters.

The volume gives the link: base times height is 500.

x2h = 500

So h = 500/x².

h = 500x2

Put it in place of h.

S = x2 + 4x × 500x2

One x cancels: S = x² + 2000 over x.

= x2 + 2000x

4 Which x make sense

A length is positive: x is more than 0.

x > 0 =

5 Slope = 0

The smallest value is where the slope is 0.

x² gives 2x.

2000/x is 2000x to the power −1, which gives −2000/x².

S′(x) = 2x − 2000x2
2000x = 2000x−1 → −2000x−2

Set it to 0, and move the fraction across.

2x = 2000x2

Times both sides by x², so they stay equal.

2x3 = 2000

Divide by 2.

x3 = 1000

The cube root of 1000 is 10, because 10 × 10 × 10 = 1000.

x = 3√1000 = 10

6 Make sure it is the smallest

Before 10, the slope is negative: going down.

After it, positive: going up.

Down, then up: the bottom.

A minimum.

S′(9) = −6.69 < 0 ↘, S′(11) = 5.47 > 0 ↗

7 Answer the question

The height: 500/100 is 5.

h = 500102 = 5

So the least material is 300 cm²: a base 10 by 10, 5 high.

S(10) = 102 + 200010 = 100 + 200 = 300 cm²

8 Check

Let's check with x a bit smaller: 9 gives 303.22.

x = 9: S = 303.22

And x = 11 gives 302.82.

Both are bigger than 300.

Right!

x = 11: S = 302.82

Let's look back.

First: draw and name.

Then: write the material.

Then: use only one letter.

Then: which x make sense.

Then: slope = 0.

Then: make sure it is the smallest.

Then: answer the question.

Last: check.

Answer
S(10) = 102 + 200010 = 100 + 200 = 300 cm²

Your turn

Try this one yourself, then check:

Show the answer
least material = 12 cm²

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