Steply

Are (1, 2, -1) and (3, 0, 3) orthogonal

Step by step, with the reason for every step · Dot product and length · Linear Algebra

Step by step

The question

Question: are (1, 2, −1) and (3, 0, 3) orthogonal?

u = [1; 2; −1], v = [3; 0; 3]

Orthogonal means perpendicular: at a right angle.

Two vectors are orthogonal exactly when their dot product is 0.

orthogonal: at a right angle (perpendicular)
u • v = 0

1 Find the dot product

Matching entries multiplied, then added: 1 × 3 + 2 × 0 + (−1) × 3.

u • v = 1 × 3 + 2 × 0 + (−1) × 3

We work out each times.

u • v = 3 + 0 − 3

Then we add: u • v = 0.

u • v = 0

2 Compare with 0

The dot product is 0.

So yes: the vectors are orthogonal.

= orthogonal

Careful!

Only a dot product of exactly 0 means orthogonal.

Any other number, even a small one, means not.

Careful: orthogonal: the dot product is exactly 0

3 Check

Let's check with Pythagoras.

At a right angle, the length of u squared plus the length of v squared equals the length of u plus v, squared.

right angle: ‖u‖2 + ‖v‖2 = ‖u + v‖2

The length squared is the entries squared, added.

For u: 6.

‖u‖² = 12 + 22 + (−1)2 = 1 + 4 + 1 = 6

For v: 18.

‖v‖² = 32 + 02 + 32 = 9 + 0 + 9 = 18

u plus v: (4, 2, 2).

u + v = [4; 2; 2]

Its length squared: 24.

‖u + v‖² = 42 + 22 + 22 = 16 + 4 + 4 = 24

6 plus 18 is 24, the same as 24.

Pythagoras works: a right angle.

So the answer is right!

6 + 18 = 24 = 24

Let's look back.

First: find the dot product.

Then: compare with 0.

Last: check.

Answer
Careful: orthogonal: the dot product is exactly 0

Your turn

Try this one yourself, then check:

Orthogonal? [3; 4; −1] and [2; 0; 6]
Show the answer
orthogonal

More from Dot product and length

The whole lesson: Dot product and length →