Steply

Area of one petal of r = cos(3θ)

Step by step, with the reason for every step · Area in polar coordinates · Calculus 2

Step by step

The question

Question: find the area of one petal r = cos(3θ).

r = cos(3θ)

1 Draw it

A polar grid: circles around the center, and a line for each angle.

For each angle θ, go out a distance r.

It makes 3 petals.

We want one petal: this one.

2 One trip around

One petal starts and ends at the center, where r = 0.

cos of 3θ is 0 at θ = −π/6 and θ = π/6.

θ from −π/6 to π/6

3 Write the integral

Cut the area into thin slices from the center.

Each is almost a thin triangle: one half r squared dθ, like a slice of a circle.

slice ≈ 12r2 dθ

Add up the slices: A is one half of the integral of r squared.

A = 12∫ from −π/6 to π/6 of (cos(3θ))2 dθ

Careful!

Do not forget the one half!

A slice is half of r squared dθ.

Careful: not A = ∫ r2 dθ ✗

4 Square it

Square r.

A = 12∫ from −π/6 to π/6 of (cos2(3θ)) dθ

5 Use the half-angle rule

The half-angle rule: cos squared is 1 plus cos of double the angle, over 2.

cos2 3θ = 1 + cos 6θ2

Use it, then add the plain numbers: 1/2.

= 12∫ from −π/6 to π/6 of (12 + 12 cos 6θ) dθ

6 Integrate

Integrate: a number gives the number times θ.

cos gives sin, divided by the number in front of θ.

A = 12[ 12θ + sin 6θ12 ] from −π/6 to π/6

7 Top minus bottom

Every sin part is 0 at these limits: sin of a whole number of half turns is 0.

sin 0 = sin π = sin 2π = 0

Only the θ part is left: 1/2 times the length of the interval, π/3.

= 12 × 12 × (π/6 − (−π/6))

So the area is π over 12 square units, about 0.26.

A = π12 ≈ 0.26

8 Check

Let's check with a calculator: it adds up 1000 thin slices.

That gives about 0.26, the same as our answer.

Right!

1000 thin slices: ≈ 0.26

Let's look back.

First: draw it.

Then: one trip around.

Then: write the integral.

Then: square it.

Then: use the half-angle rule.

Then: integrate.

Then: top minus bottom.

Last: check.

Answer
A = π12 ≈ 0.26

Your turn

Try this one yourself, then check:

Find the area of one petal r = 2sin(2θ)
Show the answer
A = π2

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