Steply

Center and radius of x^2 + y^2 - 8x - 8y + 16 = 0

Step by step, with the reason for every step · Circle from the general form · Geometry

Step by step

The question

Question: find the center and the radius of x² + y² − 8x − 8y + 16 = 0.

x2 + y2 − 8x − 8y + 16 = 0

1 Group x and y

Put the x terms together in a bracket, and the y terms together.

(x2 − 8x) + (y2 − 8y) + 16 = 0

2 Remove the + 16

We want only the x and y groups on the left.

To remove + 16, we take away 16.

We do it on both sides.

Why both sides?

The = sign means both sides are the same amount.

If we change only one side, they are not the same any more.

(x2 − 8x) + (y2 − 8y) + 16 − 16 = 0 − 16

+ 16 and − 16 make zero.

Cross them out.

0 minus 16 is −16.

(x2 − 8x) + (y2 − 8y) = −16

3 Complete the square for x

To make x² − 8x a full square: half of −8 is −4.

(−4) times (−4) is 16.

So we add 16.

We do it on both sides, so they stay equal.

(x2 − 8x + 16) + (y2 − 8y) = −16 + 16
−8 ÷ 2 = −4, (−4) × (−4) = 16

Careful!

What we add on the left, we add on the right too.

Then the two sides stay equal.

Careful: add 16 on both sides

4 Complete the square for y

To make y² − 8y a full square: half of −8 is −4.

(−4) times (−4) is 16.

So we add 16.

We do it on both sides, so they stay equal.

(x2 − 8x + 16) + (y2 − 8y + 16) = −16 + 16 + 16
−8 ÷ 2 = −4, (−4) × (−4) = 16

5 Write as squares

Each bracket is now a full square.

On the right, −16 + 16 + 16 is 16.

So (x − 4)² + (y − 4)² = 16.

(x − 4)2 + (y − 4)2 = 16

x² − 8x + 16 is (x − 4)².

y² − 8y + 16 is (y − 4)².

x² − 8x + 16 = (x − 4)2
y² − 8y + 16 = (y − 4)2

6 Read the center and radius

Compare with the circle rule: (x − h)² + (y − k)² = r².

(x − h)2 + (y − k)2 = r2

The signs turn: x − 4 gives h = 4.

y − 4 gives k = 4.

x − 4 → h = 4
y − 4 → k = 4

So the center is (4, 4).

center = (4, 4)

r² is 16.

So r is the square root of 16: 4, because 4 times 4 is 16.

r = √16 = 4

So the center is (4, 4) and the radius is 4.

center (4, 4) and r = 4

7 Check

Let's check with a point on the circle: (8, 4), 4 to the right from the center.

Put it in the first equation.

8² + 4² − 8 × 8 − 8 × 4 + 16
= 64 + 16 − 64 − 32 + 16 = 0

We get 0, the same as the right side.

So the center and the radius are right!

Let's look back.

First: group x and y.

Then: remove the + 16.

Then: complete the square for x.

Then: complete the square for y.

Then: write as squares.

Then: read the center and radius.

Last: check.

Answer
center (4, 4) and r = 4

Your turn

Try this one yourself, then check:

Find the center and the radius of x2 + y2 − 10x − 2y + 22 = 0
Show the answer
center (5, 1) and r = 2

More from Circle from the general form

The whole lesson: Circle from the general form →