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Concavity and inflection points of f(x) = x^3 - 3x

Step by step, with the reason for every step · Concavity and inflection points · Calculus 1

Step by step

The question

Question: find the concavity and the inflection points of f(x) = x³ − 3x.

f(x) = x3 − 3x

Concave up means the curve bends up, like a cup.

That is where f″ is positive.

Concave down bends down, like a cap: f″ is negative.

cup concave up: f″ > 0
cap concave down: f″ < 0

1 Find f″(x)

First f′: the power rule on each term.

f′(x) = 3x^(3 − 1) − 3 × 1

Now we have f′(x) = 3x² − 3.

= 3x2 − 3

Then f″: the power rule again, on f′.

f″(x) = 3 × 2x^(2 − 1) + 0

Now we have f″(x) = 6x.

= 6x

2 Solve f″(x) = 0

The bending can only change where f″ is 0.

So we solve f″(x) = 0.

f″(x) = 0
6x = 0

6x is 0 only when x is 0.

6x = 0 → x = 0

So x = 0.

x = 0

3 Sign table for f″

A sign table for f″.

The number 0 cuts the line into 2 parts.

Test one number in each part: −1, 1.

f″(−1) = −6, f″(1) = 6

f″(−1) is −6: negative.

So f bends down there: a cap.

cap

f″(1) is 6: positive.

So f bends up there: a cup.

cup
0

Careful!

Concave up is about the bending, not about going up.

A cup can go down on one side.

Careful: concave up is not "going up"

4 Inflection points

At x = 0, the bending changes: an inflection point.

infl.

Its y: put 0 into f.

We get 0.

f(0) = 03 − 3(0) = 0 + 0 = 0

f is concave up where f″ is positive: x > 0.

up ∪ : x > 0

f is concave down where f″ is negative: x < 0.

down ∩ : x < 0

And the inflection point is (0, 0).

inflection : (0, 0)

5 Check

Let's check with the graph.

A cap, then a cup.

It changes at the inflection point.

Right!

Let's look back.

First: find f″(x).

Then: solve f″(x) = 0.

Then: sign table for f″.

Then: inflection points.

Last: check.

Answer
inflection : (0, 0)

Your turn

Try this one yourself, then check:

Find the concavity and the inflection points of f(x) = x3 − 3x + 1
Show the answer
concave up: x > 0; concave down: x < 0; inflection: (0, 1)

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