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Concavity and inflection points of f(x) = x^3 - 9x^2 + 24x

Step by step, with the reason for every step · Concavity and inflection points · Calculus 1

Step by step

The question

Question: find the concavity and the inflection points of f(x) = x³ − 9x² + 24x.

f(x) = x3 − 9x2 + 24x

Concave up means the curve bends up, like a cup.

That is where f″ is positive.

Concave down bends down, like a cap: f″ is negative.

cup concave up: f″ > 0
cap concave down: f″ < 0

1 Find f″(x)

First f′: the power rule on each term.

f′(x) = 3x^(3 − 1) − 9 × 2x^(2 − 1) + 24 × 1

Now we have f′(x) = 3x² − 18x + 24.

= 3x2 − 18x + 24

Then f″: the power rule again, on f′.

f″(x) = 3 × 2x^(2 − 1) − 18 × 1 + 0

Now we have f″(x) = 6x − 18.

= 6x − 18

2 Solve f″(x) = 0

The bending can only change where f″ is 0.

So we solve f″(x) = 0.

f″(x) = 0
6x − 18 = 0

Take out the 6.

6(x − 3) = 0

So x = 3.

x = 3

3 Sign table for f″

A sign table for f″.

The number 3 cuts the line into 2 parts.

Test one number in each part: 2, 4.

f″(2) = −6, f″(4) = 6

f″(2) is −6: negative.

So f bends down there: a cap.

cap

f″(4) is 6: positive.

So f bends up there: a cup.

cup
0

Careful!

Concave up is about the bending, not about going up.

A cup can go down on one side.

Careful: concave up is not "going up"

4 Inflection points

At x = 3, the bending changes: an inflection point.

infl.

Its y: put 3 into f.

We get 18.

f(3) = 33 − 9(3)2 + 24(3) = 27 − 81 + 72 = 18

f is concave up where f″ is positive: x > 3.

up ∪ : x > 3

f is concave down where f″ is negative: x < 3.

down ∩ : x < 3

And the inflection point is (3, 18).

inflection : (3, 18)

5 Check

Let's check with the graph.

A cap, then a cup.

It changes at the inflection point.

Right!

Let's look back.

First: find f″(x).

Then: solve f″(x) = 0.

Then: sign table for f″.

Then: inflection points.

Last: check.

Answer
inflection : (3, 18)

Your turn

Try this one yourself, then check:

Find the concavity and the inflection points of f(x) = x3 − 3x2 + 5x + 2
Show the answer
concave up: x > 1; concave down: x < 1; inflection: (1, 5)

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