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Where is f(x) = -x^3 + 3x concave up

Step by step, with the reason for every step · Concavity and inflection points · Calculus 1

Step by step

The question

Question: find where f(x) = −x³ + 3x is concave up and where it is concave down.

f(x) = −x3 + 3x

Concave up means the curve bends up, like a cup.

That is where f″ is positive.

Concave down bends down, like a cap: f″ is negative.

cup concave up: f″ > 0
cap concave down: f″ < 0

1 Find f″(x)

First f′: the power rule on each term.

f′(x) = −3x^(3 − 1) + 3 × 1

Now we have f′(x) = −3x² + 3.

= −3x2 + 3

Then f″: the power rule again, on f′.

f″(x) = −3 × 2x^(2 − 1) + 0

Now we have f″(x) = −6x.

= −6x

2 Solve f″(x) = 0

The bending can only change where f″ is 0.

So we solve f″(x) = 0.

f″(x) = 0
−6x = 0

−6x is 0 only when x is 0.

−6x = 0 → x = 0

So x = 0.

x = 0

3 Sign table for f″

A sign table for f″.

The number 0 cuts the line into 2 parts.

Test one number in each part: −1, 1.

f″(−1) = 6, f″(1) = −6

f″(−1) is 6: positive.

So f bends up there: a cup.

cup

f″(1) is −6: negative.

So f bends down there: a cap.

cap
0

Careful!

Concave up is about the bending, not about going up.

A cup can go down on one side.

Careful: concave up is not "going up"

4 Inflection points

At x = 0, the bending changes: an inflection point.

infl.

Its y: put 0 into f.

We get 0.

f(0) = −(0)3 + 3(0) = 0 + 0 = 0

f is concave up where f″ is positive: x < 0.

up ∪ : x < 0

f is concave down where f″ is negative: x > 0.

down ∩ : x > 0

5 Check

Let's check with the graph.

A cup, then a cap.

It changes at the inflection point.

Right!

Let's look back.

First: find f″(x).

Then: solve f″(x) = 0.

Then: sign table for f″.

Then: inflection points.

Last: check.

Answer
down ∩ : x > 0

Your turn

Try this one yourself, then check:

Find where f(x) = −x3 + 4x − 1
Show the answer
concave up: x < 0; concave down: x > 0

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