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Cumulative frequency: 0-20: 5, 20-40: 11, 40-60: 12, 60-80: 4, find…

Step by step, with the reason for every step · Cumulative frequency · Statistics

Step by step

The question

Question: for the groups 0-20: 5, 20-40: 11, 40-60: 12, 60-80: 4, find the median.

0-20: 5, 20-40: 11, 40-60: 12, 60-80: 4

1 Running total

A table of the groups.

We add a column: the cumulative frequency, the running total.

Each total adds the next frequency on: 5, 5 + 11 = 16, 16 + 12 = 28, and so on, up to 32.

2 Plot at the class ends

Across: the values.

Up: the running total.

The graph starts at 0, with 0: nobody is below the first class.

Each total goes at the END of its class: 5 at 20, because by 20 all 5 have been counted.

Careful!

The running total counts everything up to the end of the class.

So the point goes at the end.

Careful: plot at the END of each class, not the middle

3 Join the points

We join the points from left to right.

4 Median

The median is the middle value.

Half of 32 is 16.

From 16 on the up scale, across to the line, then down: about 40.

So the median is about 40.

median = read at 32 ÷ 2 = 16: ≈ 40

5 Check

Let's check: the last running total is 32, all the frequencies added.

And the reading is inside its class.

So it fits!

last total = 5 + 11 + 12 + 4 = 32

Let's look back.

First: running total.

Then: plot at the class ends.

Then: join the points.

Then: median.

Last: check.

Answer
median = read at 32 ÷ 2 = 16: ≈ 40

Your turn

Try this one yourself, then check:

For the groups 0-20: 7, 20-40: 11, 40-60: 11, 60-80: 7
Show the answer
median ≈ 40

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