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Cumulative frequency: 0-20: 8, 20-40: 16, 40-60: 12, 60-80: 4, find…

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The question

Question: for the groups 0-20: 8, 20-40: 16, 40-60: 12, 60-80: 4, find the interquartile range.

0-20: 8, 20-40: 16, 40-60: 12, 60-80: 4

1 Running total

A table of the groups.

We add a column: the cumulative frequency, the running total.

Each total adds the next frequency on: 8, 8 + 16 = 24, 24 + 12 = 36, and so on, up to 40.

2 Plot at the class ends

Across: the values.

Up: the running total.

The graph starts at 0, with 0: nobody is below the first class.

Each total goes at the END of its class: 8 at 20, because by 20 all 8 have been counted.

Careful!

The running total counts everything up to the end of the class.

So the point goes at the end.

Careful: plot at the END of each class, not the middle

3 Join the points

We join the points from left to right.

4 Quartiles

The lower quartile is a quarter of the way up: 40 divided by 4 is 10.

From 10 on the up scale, across to the line, then down: about 22.5.

So Q 1 is about 22.5.

Q1 = read at 40 ÷ 4 = 10: ≈ 22.5

The upper quartile is three quarters of the way up: 30.

From 30 on the up scale, across to the line, then down: about 50.

So Q 3 is about 50.

Q3 = read at 3 × 10 = 30: ≈ 50

5 Interquartile range

The interquartile range is Q3 minus Q1: about 27.5.

The middle half of the values lies in this range.

IQR ≈ 50 − 22.5 = 27.5

6 Check

Let's check: the last running total is 40, all the frequencies added.

And the reading is inside its class.

So it fits!

last total = 8 + 16 + 12 + 4 = 40

Let's look back.

First: running total.

Then: plot at the class ends.

Then: join the points.

Then: quartiles.

Then: interquartile range.

Last: check.

Answer
IQR ≈ 50 − 22.5 = 27.5

Your turn

Try this one yourself, then check:

For the groups 0-20: 9, 20-40: 18, 40-60: 11, 60-80: 2
Show the answer
IQR ≈ 24.4

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