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Cumulative frequency

Running total, graph, median, quartiles · Statistics · 20 problems, easy to harder

▶ Watch the first one solved

How we do it

  1. Running total
  2. Plot at the class ends
  3. Join the points
  4. Quartiles
  5. Interquartile range
  6. Check

The steps for Cumulative frequency: 0-30: 12, 30-60: 28, 60-90: 24, 90-120: 16…. Every solution names its steps, so you always know what comes next.

Worked examples

Cumulative frequency: 0-10: 4, 10-20: 9, 20-30: 15, 30-40: 8, 40-50… Easy

The question

Question: for the groups 0-10: 4, 10-20: 9, 20-30: 15, 30-40: 8, 40-50: 4, find the median.

0-10: 4, 10-20: 9, 20-30: 15, 30-40: 8, 40-50: 4

1 Running total

A table of the groups.

We add a column: the cumulative frequency, the running total.

Each total adds the next frequency on: 4, 4 + 9 = 13, 13 + 15 = 28, and so on, up to 40.

2 Plot at the class ends

Across: the values.

Up: the running total.

The graph starts at 0, with 0: nobody is below the first class.

Each total goes at the END of its class: 4 at 10, because by 10 all 4 have been counted.

Careful!

The running total counts everything up to the end of the class.

So the point goes at the end.

Careful: plot at the END of each class, not the middle

3 Join the points

We join the points from left to right.

4 Median

The median is the middle value.

Half of 40 is 20.

From 20 on the up scale, across to the line, then down: about 24.7.

So the median is about 24.7.

median = read at 40 ÷ 2 = 20: ≈ 24.7

5 Check

Let's check: the last running total is 40, all the frequencies added.

And the reading is inside its class.

So it fits!

last total = 4 + 9 + 15 + 8 + 4 = 40

Let's look back.

First: running total.

Then: plot at the class ends.

Then: join the points.

Then: median.

Last: check.

Answer
median = read at 40 ÷ 2 = 20: ≈ 24.7

▶ Watch it solved

Cumulative frequency: 0-10: 4, 10-20: 9, 20-30: 15, 30-40: 8, 40-50… Medium

The question

Question: for the groups 0-10: 4, 10-20: 9, 20-30: 15, 30-40: 8, 40-50: 4, find the lower quartile.

0-10: 4, 10-20: 9, 20-30: 15, 30-40: 8, 40-50: 4

1 Running total

A table of the groups.

We add a column: the cumulative frequency, the running total.

Each total adds the next frequency on: 4, 4 + 9 = 13, 13 + 15 = 28, and so on, up to 40.

2 Plot at the class ends

Across: the values.

Up: the running total.

The graph starts at 0, with 0: nobody is below the first class.

Each total goes at the END of its class: 4 at 10, because by 10 all 4 have been counted.

Careful!

The running total counts everything up to the end of the class.

So the point goes at the end.

Careful: plot at the END of each class, not the middle

3 Join the points

We join the points from left to right.

4 Quartiles

The lower quartile is a quarter of the way up: 40 divided by 4 is 10.

From 10 on the up scale, across to the line, then down: about 16.7.

So Q 1 is about 16.7.

Q1 = read at 40 ÷ 4 = 10: ≈ 16.7

5 Check

Let's check: the last running total is 40, all the frequencies added.

And the reading is inside its class.

So it fits!

last total = 4 + 9 + 15 + 8 + 4 = 40

Let's look back.

First: running total.

Then: plot at the class ends.

Then: join the points.

Then: quartiles.

Last: check.

Answer
Q1 = read at 40 ÷ 4 = 10: ≈ 16.7

▶ Watch it solved

Cumulative frequency: 0-30: 12, 30-60: 28, 60-90: 24, 90-120: 16… Harder

The question

Question: for the groups 0-30: 12, 30-60: 28, 60-90: 24, 90-120: 16, find the interquartile range.

0-30: 12, 30-60: 28, 60-90: 24, 90-120: 16

1 Running total

A table of the groups.

We add a column: the cumulative frequency, the running total.

Each total adds the next frequency on: 12, 12 + 28 = 40, 40 + 24 = 64, and so on, up to 80.

2 Plot at the class ends

Across: the values.

Up: the running total.

The graph starts at 0, with 0: nobody is below the first class.

Each total goes at the END of its class: 12 at 30, because by 30 all 12 have been counted.

Careful!

The running total counts everything up to the end of the class.

So the point goes at the end.

Careful: plot at the END of each class, not the middle

3 Join the points

We join the points from left to right.

4 Quartiles

The lower quartile is a quarter of the way up: 80 divided by 4 is 20.

From 20 on the up scale, across to the line, then down: about 38.6.

So Q 1 is about 38.6.

Q1 = read at 80 ÷ 4 = 20: ≈ 38.6

The upper quartile is three quarters of the way up: 60.

From 60 on the up scale, across to the line, then down: about 85.

So Q 3 is about 85.

Q3 = read at 3 × 20 = 60: ≈ 85

5 Interquartile range

The interquartile range is Q3 minus Q1: about 46.4.

The middle half of the values lies in this range.

IQR ≈ 85 − 38.6 = 46.4

6 Check

Let's check: the last running total is 80, all the frequencies added.

And the reading is inside its class.

So it fits!

last total = 12 + 28 + 24 + 16 = 80

Let's look back.

First: running total.

Then: plot at the class ends.

Then: join the points.

Then: quartiles.

Then: interquartile range.

Last: check.

Answer
IQR ≈ 85 − 38.6 = 46.4

▶ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. cumulative frequency: 0-10: 4, 10-20: 9, 20-30: 15, 30-40: 8, 40-50: 4, find the median
    Answer
    median = read at 40 ÷ 2 = 20: ≈ 24.7
  2. cumulative frequency: 0-10: 2, 10-20: 6, 20-30: 10, 30-40: 2, find the median
    Answer
    median = read at 20 ÷ 2 = 10: ≈ 22
  3. cumulative frequency: 0-5: 3, 5-10: 7, 10-15: 6, 15-20: 4, find the median
    Answer
    median = read at 20 ÷ 2 = 10: ≈ 10
  4. cumulative frequency: 0-20: 5, 20-40: 11, 40-60: 12, 60-80: 4, find the median
    Answer
    median = read at 32 ÷ 2 = 16: ≈ 40
  5. cumulative frequency: 10-20: 4, 20-30: 8, 30-40: 12, 40-50: 8, 50-60: 8, find the median
    Answer
    median = read at 40 ÷ 2 = 20: ≈ 36.7
  6. cumulative frequency: 0-10: 6, 10-20: 10, 20-30: 4, find the median
    Answer
    median = read at 20 ÷ 2 = 10: ≈ 14
  7. cumulative frequency: 0-4: 2, 4-8: 6, 8-12: 8, 12-16: 4, find the median
    Answer
    median = read at 20 ÷ 2 = 10: ≈ 9

Medium

  1. cumulative frequency: 0-10: 4, 10-20: 9, 20-30: 15, 30-40: 8, 40-50: 4, find the lower quartile
    Answer
    Q1 = read at 40 ÷ 4 = 10: ≈ 16.7
  2. cumulative frequency: 0-10: 4, 10-20: 9, 20-30: 15, 30-40: 8, 40-50: 4, find the upper quartile
    Answer
    Q3 = read at 3 × 10 = 30: ≈ 32.5
  3. cumulative frequency: 0-10: 4, 10-20: 9, 20-30: 15, 30-40: 8, 40-50: 4, find the interquartile range
    Answer
    IQR ≈ 32.5 − 16.7 = 15.8
  4. cumulative frequency: 0-20: 8, 20-40: 16, 40-60: 12, 60-80: 4, find the interquartile range
    Answer
    IQR ≈ 50 − 22.5 = 27.5
  5. cumulative frequency: 0-5: 4, 5-10: 8, 10-15: 12, 15-20: 8, 20-25: 8, find the interquartile range
    Answer
    IQR ≈ 18.8 − 8.8 = 10
  6. cumulative frequency: 100-110: 6, 110-120: 14, 120-130: 12, 130-140: 8, find the median
    Answer
    median = read at 40 ÷ 2 = 20: ≈ 120
  7. cumulative frequency: 0-10: 10, 10-20: 20, 20-30: 30, 30-40: 20, find the upper quartile
    Answer
    Q3 = read at 3 × 20 = 60: ≈ 30

Harder

  1. cumulative frequency: 0-30: 12, 30-60: 28, 60-90: 24, 90-120: 16, find the interquartile range
    Answer
    IQR ≈ 85 − 38.6 = 46.4
  2. cumulative frequency: 140-150: 4, 150-160: 12, 160-170: 20, 170-180: 10, 180-190: 2, find the interquartile range
    Answer
    IQR ≈ 170 − 156.7 = 13.3
  3. cumulative frequency: 0-2: 6, 2-4: 14, 4-6: 22, 6-8: 10, 8-10: 8, find the median
    Answer
    median = read at 60 ÷ 2 = 30: ≈ 4.9
  4. cumulative frequency: 0-10: 3, 10-20: 7, 20-30: 18, 30-40: 22, 40-50: 10, find the interquartile range
    Answer
    IQR ≈ 37.7 − 22.8 = 14.9
  5. cumulative frequency: 20-40: 10, 40-60: 30, 60-80: 25, 80-100: 15, find the lower quartile
    Answer
    Q1 = read at 80 ÷ 4 = 20: ≈ 46.7
  6. cumulative frequency: 0-25: 16, 25-50: 24, 50-75: 32, 75-100: 8, find the median
    Answer
    median = read at 80 ÷ 2 = 40: ≈ 50