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Derivative of tan^-1(3x + 2)

Step by step, with the reason for every step · Derivatives of inverse trig functions · Calculus 1

Step by step

The question

Question: find the derivative of f(x) = tan⁻¹(3x + 2).

f(x) = tan⁻¹(3x + 2)

1 The rule

The rule: the derivative of tan⁻¹ u is 1/(1 + u²).

tan⁻¹ u → 11 + u²

2 The inside

There is something inside: 3x + 2.

Call it u.

u = 3x + 2

3 The outside

First the outside: the rule on tan⁻¹ u.

dydu = 11 + u²

4 The inside's slope

The inside's slope: the power rule on 3x + 2 gives 3.

dudx = 3

5 Multiply

The chain rule: multiply the two, and put 3x + 2 back in place of u.

f′(x) = 11 + (3x + 2)2 × 3

Careful!

Do not stop at the outside.

Multiply by the inside's slope, 3.

Careful: not 11 + (3x + 2)2 ✗

Tidy up: f′(x) = 3/(1 + (3x + 2)²).

= 31 + (3x + 2)2

6 Check

Let's check: the derivative is the slope.

At x = 1, our answer gives 0.1154, with a calculator in radians.

f′(1) = 0.1154

Now the slope between two very close points: x = 1 and x = 1.001.

A calculator gives about 0.12.

Very close to 0.1154.

Right!

f(1.001) − f(1)0.001 ≈ 0.12

Let's look back.

First: the rule.

Then: the inside.

Then: the outside.

Then: the inside's slope.

Then: multiply.

Last: check.

Answer
= 31 + (3x + 2)2

Your turn

Try this one yourself, then check:

f(x) = tan⁻¹(2x + 5)
Show the answer
f′(x) = 21 + (2x + 5)2

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