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Derivative of 2sin^-1(x^2)

Step by step, with the reason for every step · Derivatives of inverse trig functions · Calculus 1

Step by step

The question

Question: find the derivative of f(x) = 2sin⁻¹(x²).

f(x) = 2sin⁻¹(x2)

1 The rule

The rule: the derivative of sin⁻¹ u is 1 over √(1 − u²).

sin⁻¹ u → 1√1 − u²

2 The inside

There is something inside: x².

Call it u.

u = x2

3 The outside

First the outside: the rule on sin⁻¹ u.

The 2 waits.

dydu = 2 × 1√1 − u²

4 The inside's slope

The inside's slope: the power rule on x² gives 2x.

dudx = 2x

5 Multiply

The chain rule: multiply the two, and put x² back in place of u.

f′(x) = 2 × 1√1 − (x2)2 × 2x

Careful!

Do not stop at the outside.

Multiply by the inside's slope, 2x.

Careful: not 21√1 − (x2)2 ✗

Square the inside: (x²)² is x⁴.

(x2)2 = x4

Tidy up: f′(x) = 4x over √(1 − x⁴).

= 4x√1 − x4

6 Check

Let's check: the derivative is the slope.

At x = 0.5, our answer gives 2.0656, with a calculator in radians.

f′(0.5) = 2.0656

Now the slope between two very close points: x = 0.5 and x = 0.501.

A calculator gives about 2.07.

Very close to 2.0656.

Right!

f(0.501) − f(0.5)0.001 ≈ 2.07

Let's look back.

First: the rule.

Then: the inside.

Then: the outside.

Then: the inside's slope.

Then: multiply.

Last: check.

Answer
= 4x√1 − x4

Your turn

Try this one yourself, then check:

Find the derivative of f(x) = 5sin⁻¹(x2)
Show the answer
f′(x) = 10x√1 − x4

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