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Diagonal of a box 5 m by 6 m by 8 m

Step by step, with the reason for every step · Pythagoras in 3D · Geometry

Step by step

The question

Question: find the diagonal of a box 5 m by 6 m by 8 m.

box 5 m by 6 m by 8 m

The diagonal goes from a bottom corner to the top corner on the other side, right through the box.

1 Floor diagonal

First the floor.

Its diagonal d makes a right triangle with the sides 5 and 6.

Pythagoras: d squared is 5 squared plus 6 squared.

5 times 5 is 25.

6 times 6 is 36.

Together 61.

d2 = 52 + 62 = 25 + 36 = 61
a² + b² = c²

61 is not a square number.

We do not need d itself: the next step uses d squared.

keep d² = 61

Careful!

We cannot just add the sides.

A diagonal is a short cut: Pythagoras, twice.

Careful: not 5 + 6 + 8 = 19 ✗

2 Diagonal of the box

Now a new right triangle stands up: the floor diagonal d, the height 8, and the diagonal D of the box.

Pythagoras again: D squared is d squared plus 8 squared.

d squared is 61.

8 times 8 is 64.

Together 125.

D2 = d2 + 82 = 61 + 64 = 125

125 is not a square number.

A calculator gives 11.180, and so on.

D = √125 = 11.180…

To the nearest tenth, D is about 11.2 m.

D ≈ 11.2 m

3 Check

Let's check: the two steps are the same as l squared plus w squared plus h squared.

25 plus 36 plus 64 is 125, the same D squared.

So the answer is right!

5² + 6² + 8² = 25 + 36 + 64 = 125

Let's look back.

First: floor diagonal.

Then: diagonal of the box.

Last: check.

Answer
D ≈ 11.2 m

Your turn

Try this one yourself, then check:

box 6 m by 6 m by 9 m
Show the answer
D ≈ 12.4 m

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