Steply

$2000 grows by 3% a year. How many years until it is $2600?

Step by step, with the reason for every step · Half-life and time with logs · Algebra 2

Step by step

The question

Question: $2000 grows by 3% a year.

How many years until it is $2600?

1 Write the equation

The compound interest rule, with n = 1: once a year.

A = P(1 + rn)nt, n = 1

We know the start, $2000, and the end, $2600.

t is the unknown, up in the power.

2000 × 1.03t = 2600

2 Get the power alone

To remove times 2000, we divide by 2000.

We do it on both sides.

Why both sides?

The = sign means both sides are the same amount.

If we change only one side, they are not the same any more.

2000 × 1.03t2000 = 26002000

2000 divided by 2000 is 1.

So just the power is left.

2600 divided by 2000 is 1.3.

Now we have 1.03 to the power t = 1.3.

1.03t = 1.3

Careful!

Each year it keeps all of it and gets 3% more.

So we multiply by 1.03, not by 0.03.

Careful: the factor is 1 + 0.03 = 1.03, not 0.03

3 Take the log of both sides

Logs bring a power down.

So we take the log of both sides.

We do it on both sides, so they stay equal.

log(1.03t) = log 1.3

4 Bring the power down

The power rule for logs: the power comes down in front, as times.

log(aⁿ) = n × log a

The whole power, t, comes down in front.

t × log 1.03 = log 1.3

5 Get t alone

Divide both sides by log 1.03.

So t is alone.

t = log 1.3log 1.03

6 Use a calculator

With a calculator: log 1.3 is about 0.113943.

And log 1.03 is about 0.0128372.

log 1.3 ≈ 0.113943
log 1.03 ≈ 0.0128372

So t is about 8.88 years, to two decimal places.

t ≈ 8.88

7 Check

Let's check: put t = 8.88 back in.

With a calculator.

We get about $2600.31.

2000 × 1.038.88 ≈ 2600.31

That is 2600, up to the rounding.

It works!

≈ 2600

Let's look back.

First: write the equation.

Then: get the power alone.

Then: take the log of both sides.

Then: bring the power down.

Then: get t alone.

Then: use a calculator.

Last: check.

Answer
t ≈ 8.88

Your turn

Try this one yourself, then check:

Show the answer
t ≈ 14.21 years

More from Half-life and time with logs

The whole lesson: Half-life and time with logs →