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Domain of f(x) = √(x - 2)

Step by step, with the reason for every step · Domain and range · Algebra 2

Step by step

The question

Question: find the domain of f(x) = √(x − 2).

f(x) = √x − 2

The domain is all the x's we can put in.

domain = the x's that can go in

1 The inside is 0 or more

No real number times itself is negative.

3 times 3 is 9.

Minus 3 times minus 3 is 9 too.

So we can't take the square root of a negative number.

√ of a negative: not allowed
3 × 3 = 9, (−3) × (−3) = 9

So the inside, x − 2, must be 0 or more.

x − 2 ≥ 0

2 Remove the − 2

We want x by itself.

The − 2 is in the way.

To remove − 2, we add 2.

We do it on both sides, so the sign stays true.

x − 2 + 2 ≥ 0 + 2

− 2 and + 2 make zero.

Cross them out.

0 + 2 = 2.

0 + 2 = 2

So x is greater than or equal to 2.

x ≥ 2

These are the x's that can go in.

So the domain is x ≥ 2.

3 Show it on a number line

Books also write the answer like this.

It is called interval notation.

A square bracket means the end is in, like the filled circle.

∞ means it goes on for ever.

interval: [2, ∞)

4 Check

Let's check.

Put 1 in, just outside.

The inside is −1: negative.

Not allowed.

x = 1: √1 − 2 = √−1 not allowed

Now 3, inside: the inside is 1, and the square root of 1 is 1.

It works.

x = 3: √3 − 2 = √1 = 1

Let's look back.

First: the inside is 0 or more.

Then: remove the − 2.

Then: show it on a number line.

Last: check.

Answer
x ≥ 2

Your turn

Try this one yourself, then check:

domain of f(x) = √x − 7
Show the answer
domain: x ≥ 7

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