Steply

Double integral of 1 over the region between y = x and y = x^2

Step by step, with the reason for every step · Double integrals over general regions · Calculus 3

Step by step

The question

Question: find the double integral of 1 over the region between y = x and y = x².

∫ ∫ 1 dA, between y = x and y = x²

1 Draw the region

Draw the grid.

Draw y = x

and y = x².

The region is between them.

Where do they meet?

Where the two heights are equal.

x = x2

Bring everything to one side.

x − x2 = 0

Take out x.

x(1 − x) = 0

So they meet at x = 0 and x = 1.

x = 0 or x = 1

Which is on top?

Try x = 0.5: y = x is higher.

x = 0.5: x → 0.5, x² → 0.25

2 Find the limits

Take a thin upright strip.

On it, y goes from the bottom curve up to the top curve.

So inside, y goes from x² to x.

Outside, x goes from 0 to 1.

∫ ∫ 1 dA = ∫ from 0 to 1 of ∫ from x² to x of 1 dy dx

Careful!

The inside integral is dy, so its limits are the y limits.

They may have x in them.

The outside limits are only numbers.

Careful: dy inside: the y limits go inside

3 The inner integral

Inside first: integrate in y.

x stays fixed, like a plain number.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from x² to x of 1 dy = y from x² to x

Put in the top y = x, then take away the bottom y = x².

∫ from x² to x of 1 dy = (x) − (x2)

So it is x − x².

∫ from x² to x of 1 dy = x − x2

4 The outer integral

Now the outside integral, in x.

Its limits are numbers.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from 0 to 1 of (x − x2) dx = [x22 − x33] from 0 to 1

Put in the top x = 1, then take away the bottom x = 0.

∫ from 0 to 1 of (x − x2) dx = ((1)22 − (1)33) − ((0)22 − (0)33)

The bottom part is 0.

So it is 1/6.

∫ from 0 to 1 of (x − x2) dx = 16

5 Check

Let's check if it makes sense.

The region's area is 1/6.

On it, f goes from 1 to 1.

area = 1/6, f from 1 to 1

So the answer must be between 0.167 and 0.167.

0.167 is.

Right!

0.167 ≤ 0.167 ≤ 0.167

Let's look back.

First: draw the region.

Then: find the limits.

Then: the inner integral.

Then: the outer integral.

Last: check.

Answer
∫ from 0 to 1 of (x − x2) dx = 16

Your turn

Try this one yourself, then check:

∫ ∫ 4 dA, between y = x and y = x²
Show the answer
23

More from Double integrals over general regions

The whole lesson: Double integrals over general regions →