Steply

Double integral of 2x over 0 ≤ x ≤ 2, x^2 ≤ y ≤ 2x

Step by step, with the reason for every step · Double integrals over general regions · Calculus 3

Step by step

The question

Question: find the double integral of 2x/0 ≤ x ≤ 2, x² ≤ y ≤ 2x.

∫ ∫ 2x dA, 0 ≤ x ≤ 2, x2 ≤ y ≤ 2x

1 Draw the region

Draw the grid.

Draw y = 2x

and y = x².

The region is between them.

2 Find the limits

Take a thin upright strip.

On it, y goes from the bottom curve up to the top curve.

So inside, y goes from x² to 2x.

Outside, x goes from 0 to 2.

∫ ∫ 2x dA = ∫ from 0 to 2 of ∫ from x² to 2x of 2x dy dx

Careful!

The inside integral is dy, so its limits are the y limits.

They may have x in them.

The outside limits are only numbers.

Careful: dy inside: the y limits go inside

3 The inner integral

Inside first: integrate in y.

x stays fixed, like a plain number.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from x² to 2x of 2x dy = 2xy from x² to 2x

Put in the top y = 2x, then take away the bottom y = x².

∫ from x² to 2x of 2x dy = 2x(2x) − 2x(x2)

So it is 4x² − 2x³.

∫ from x² to 2x of 2x dy = 4x2 − 2x3

4 The outer integral

Now the outside integral, in x.

Its limits are numbers.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from 0 to 2 of (4x2 − 2x3) dx = [4x33 − x42] from 0 to 2

Put in the top x = 2, then take away the bottom x = 0.

∫ from 0 to 2 of (4x2 − 2x3) dx = (4(2)33 − (2)42) − (4(0)33 − (0)42)

The bottom part is 0.

So it is 8/3.

∫ from 0 to 2 of (4x2 − 2x3) dx = 83

5 Check

Let's check if it makes sense.

The region's area is 4/3.

On it, f goes from 0 to 4.

area = 4/3, f from 0 to 4

So the answer must be between 0 and 5.333.

2.667 is.

Right!

0 ≤ 2.667 ≤ 5.333

Let's look back.

First: draw the region.

Then: find the limits.

Then: the inner integral.

Then: the outer integral.

Last: check.

Answer
∫ from 0 to 2 of (4x2 − 2x3) dx = 83

Your turn

Try this one yourself, then check:

Find the double integral of ∫ ∫ 3x dA, 0 ≤ x ≤ 2, x2 ≤ y ≤ 2x
Show the answer
4

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