Steply

Double integral of y over 0 ≤ x ≤ 1, x^2 ≤ y ≤ x

Step by step, with the reason for every step · Double integrals over general regions · Calculus 3

Step by step

The question

Question: find the double integral of y/0 ≤ x ≤ 1, x² ≤ y ≤ x.

∫ ∫ y dA, 0 ≤ x ≤ 1, x2 ≤ y ≤ x

1 Draw the region

Draw the grid.

Draw y = x

and y = x².

The region is between them.

2 Find the limits

Take a thin upright strip.

On it, y goes from the bottom curve up to the top curve.

So inside, y goes from x² to x.

Outside, x goes from 0 to 1.

∫ ∫ y dA = ∫ from 0 to 1 of ∫ from x² to x of y dy dx

Careful!

The inside integral is dy, so its limits are the y limits.

They may have x in them.

The outside limits are only numbers.

Careful: dy inside: the y limits go inside

3 The inner integral

Inside first: integrate in y.

x stays fixed, like a plain number.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from x² to x of y dy = y22 from x² to x

Put in the top y = x, then take away the bottom y = x².

∫ from x² to x of y dy = (x)22 − (x2)22

So it is x² over 2 − x⁴ over 2.

∫ from x² to x of y dy = x22 − x42

4 The outer integral

Now the outside integral, in x.

Its limits are numbers.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from 0 to 1 of (x22 − x42) dx = [x36 − x510] from 0 to 1

Put in the top x = 1, then take away the bottom x = 0.

∫ from 0 to 1 of (x22 − x42) dx = ((1)36 − (1)510) − ((0)36 − (0)510)

The bottom part is 0.

So it is 1/15.

∫ from 0 to 1 of (x22 − x42) dx = 115

5 Check

Let's check if it makes sense.

The region's area is 1/6.

On it, f goes from 0 to 1.

area = 1/6, f from 0 to 1

So the answer must be between 0 and 0.167.

0.067 is.

Right!

0 ≤ 0.067 ≤ 0.167

Let's look back.

First: draw the region.

Then: find the limits.

Then: the inner integral.

Then: the outer integral.

Last: check.

Answer
∫ from 0 to 1 of (x22 − x42) dx = 115

Your turn

Try this one yourself, then check:

Find the double integral of ∫ ∫ 4y dA, 0 ≤ x ≤ 1, x2 ≤ y ≤ x
Show the answer
415

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